Adding new nodes based on the number of existing nodes using XSLT

StackOverflow https://stackoverflow.com/questions/23611748

  •  20-07-2023
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Question

I want to modify the following xml using XSLT:

 <?xml version="1.0" encoding="UTF-8"?>
    <response>
       <folder>
          <CRDATTIM>2012-08-31-08.26.11.805400</CRDATTIM>
          <RECORDCD>F</RECORDCD>
       </folder>
       <case>
          <CRDATTIM>2014-03-26-05.22.22.339840</CRDATTIM>
          <RECORDCD>C</RECORDCD>
          <issue>
             <KEY>2014-03-26-05.22.22.193840T01</KEY>
             <PRTY>999</PRTY>
          </issue>
       </case>
       <folder>
          <CRDATTIM>2012-11-06-23.57.08.089400</CRDATTIM>
          <RECORDCD>F</RECORDCD>
       </folder>
       <case>
          <CRDATTIM>2014-04-29-06.58.32.992840</CRDATTIM>
          <RECORDCD>C</RECORDCD>
          <issue>
             <KEY>2014-04-29-06.58.31.305840T01</KEY>
             <PRTY>999</PRTY>
          </issue>
       </case>
</response>

Now, I want to add a new node <sort> to the root node <response> such that the node <sort> will contain two children <field /> and <ascending /> .But, here for each case in the above xml, the two tags <field /> and <ascending /> should be added to the <sort> node.For example in the above xml, there are two cases(<case>). So, the node <sort> should have two <field /> tags and <ascending /> tags. Ultimately, My final xml should look like below:

<?xml version="1.0" encoding="UTF-8"?>
<response>
   <folder>
      <CRDATTIM>2012-08-31-08.26.11.805400</CRDATTIM>
      <RECORDCD>F</RECORDCD>
   </folder>
   <case>
      <CRDATTIM>2014-03-26-05.22.22.339840</CRDATTIM>
      <RECORDCD>C</RECORDCD>
      <issue>
         <KEY>2014-03-26-05.22.22.193840T01</KEY>
         <PRTY>999</PRTY>
      </issue>
   </case>
   <folder>
      <CRDATTIM>2012-11-06-23.57.08.089400</CRDATTIM>
      <RECORDCD>F</RECORDCD>
   </folder>
   <case>
      <CRDATTIM>2014-04-29-06.58.32.992840</CRDATTIM>
      <RECORDCD>C</RECORDCD>
      <issue>
         <KEY>2014-04-29-06.58.31.305840T01</KEY>
         <PRTY>999</PRTY>
      </issue>
   </case>
   <sort>
      <field />
      <ascending />
      <field />
      <ascending />
      <field />
   </sort>
</response>

Please share your thoughts on how to achieve the desired functionality. Please let me know if my question is not clear. Thanks in advance.

Was it helpful?

Solution

You can use an identity template to copy the original XML and put a <sort> element on the end. See next tutorial: http://www.xmlplease.com/xsltidentity

Here is an XSLT example:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()" />
        </xsl:copy>
    </xsl:template>

    <xsl:template match="response">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()" />
            <sort>
                <xsl:for-each select="case">
                    <field />
                    <ascending />
                </xsl:for-each>
            </sort>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>
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