Get data from table using group by

Question

I have a Emptbl in which I have EmpType Column.

In EmpType I have following data for example :

E0123 
M0123
E1245
E4578
M1245
E0478
M4789
E4762

Now I want to get only those emp data which have same EmpType for example below data:

E0123
M0123
E1245
M1245 

And want to show this data as group by as 0123 and 1245

So how to get above data? I use UNION but it does not get valida data.

Thanks

Answer 1

Select A.*
    From EmpTbl A
        Inner Join
    EmpTbl B
        On  SubString(A.EmpType, 2, 4) = SubString(B.EmpType, 2, 4) And
        SubString(A.EmpType, 1, 1) <> SubString(B.EmpType , 1, 1)

Answer 2

Try this:

select substring(emptype, 2, len(emptype))
from emptbl
group by substring(emptype, 2, len(emptype))
having count(*) > 1

The hard-coded 2 is based on your sample data. If instead you had an arbitrary number of letters before the numeric part, e.g. 'ABCDEFG0123', you could use patindex to get the starting index for your substring like so;

select substring(emptype, patindex('%[0-9]%',emptype), len(emptype)

Answer 3

;with CTE as (Select Name,SUBSTRING(Name,2,5) as Number, ROW_NUMBER() 
        OVER (PARTITION By SUBSTRING(Name,2,5) ORDER BY Name) AS Row
from #Temp)

Select Temp.Name
From CTE C
     Cross Apply (Select Name FRom CTE T Where T.Number=C.Number) as Temp
Where C.Row>1

Here is the fiddle sample

Answer 4

select top 4 id from
(
select id,rn=row_number()over(partition by right(id,3) order by right(id,3)) from #t
)x

SEE IT LIVE

Answer 5

This is the smallest query that works:

select substr(a.emptype, 2) num
join emptbl a
join emptbl b on substr(a.emptype, 2) = substr(b.emptype, 2)
and a.emptype != b.emptype