Display the date, like “May 5th”, using pythons strftime? [duplicate]
Question
Possible Duplicate:
Python: Date Ordinal Output?
In Python time.strftime can produce output like "Thursday May 05" easily enough, but I would like to generate a string like "Thursday May 5th" (notice the additional "th" on the date). What is the best way to do this?
Solution
strftime
doesn't allow you to format a date with a suffix.
Here's a way to get the correct suffix:
if 4 <= day <= 20 or 24 <= day <= 30:
suffix = "th"
else:
suffix = ["st", "nd", "rd"][day % 10 - 1]
Update:
Combining a more compact solution based on Jochen's comment with gsteff's answer:
from datetime import datetime as dt
def suffix(d):
return 'th' if 11<=d<=13 else {1:'st',2:'nd',3:'rd'}.get(d%10, 'th')
def custom_strftime(format, t):
return t.strftime(format).replace('{S}', str(t.day) + suffix(t.day))
print custom_strftime('%B {S}, %Y', dt.now())
Gives:
May 5th, 2011
OTHER TIPS
This seems to add the appropriate suffix, and remove the ugly leading zeroes in the day number:
#!/usr/bin/python
import time
day_endings = {
1: 'st',
2: 'nd',
3: 'rd',
21: 'st',
22: 'nd',
23: 'rd',
31: 'st'
}
def custom_strftime(format, t):
return time.strftime(format, t).replace('{TH}', str(t[2]) + day_endings.get(t[2], 'th'))
print custom_strftime('%B {TH}, %Y', time.localtime())
"%s%s"%(day, 'trnshddt'[0xc0006c000000006c>>2*day&3::4])
But seriously, this is locale specific, so you should be doing it during internationalisation
from time import strftime
print strftime('%A %B %dth')
EDIT:
Correcting after having seen the answers of gurus:
from time import strftime
def special_strftime(dic = {'01':'st','21':'st','31':'st',
'02':'nd','22':'nd',
'03':'rd','23':'rd'}):
x = strftime('%A %B %d')
return x + dic.get(x[-2:],'th')
print special_strftime()
.
EDIT 2
Also:
from time import strftime
def special_strftime(dic = {'1':'st','2':'nd','3':'rd'}):
x = strftime('%A %B %d')
return x + ('th' if x[-2:] in ('11','12','13')
else dic.get(x[-1],'th')
print special_strftime()
.
EDIT 3
Finally, it can be simplified:
from time import strftime
def special_strftime(dic = {'1':'st','2':'nd','3':'rd'}):
x = strftime('%A %B %d')
return x + ('th' if x[-2]=='1' else dic.get(x[-1],'th')
print special_strftime()
You cannot. The time.strftime
function and the datetime.datetime.strftime
method both (usually) use the platform C library's strftime
function, and it (usually) does not offer that format. You would need to use a third-party library, like dateutil.