Python OO — member function definition and keyword self

Question

I am writting a Python class with this constructor:

      #constuctor
def __init__(self, initPt_=[1,1],fun_=Optim_tests.peaks,NITER_=30,alpha_=0.7,NMAX_=5000,FTOL_=10**(-10)):
    self.initPt = initPt_
    self.fun = fun_
    self.alpha = alpha_
    self.ITER = NITER_
    self.NMAX = NMAX_
    self.FTOL = FTOL_

and defining both member functions:

def buildSimplex(self):
    self.simplex=[]
    self.simplex.append([x for x in self.initPt])
    for i in range(len(self.initPt)):
        temp=[x for x in self.initPt]
        temp[i]=self.initPt[i]+1
        self.simplex.append(temp)
    self.npts=len(self.simplex)

def sA(self):
    self.buildSimplex()

When calling second functions, error happens:

NameError: global name 'buildSimplex' is not defined    

Do you have a clue?

Answer 1

At first sight I would say it's a identation problem, but you need to provide the actual code for a more specific answer.

The reason I'm saying this is because of the error you're getting. If you declared your class properly, and try to call a method of an instance that is not define, you should actually get a: AttributeError: A instance has no attribute 'xxxx'. And you don't need to care about the order you define your methods if they are declared in a class. See the e xample of met1 and met4 below

For example:

class A():
   def met1(self):
      print self.met4()

   def met2(self):
      self.met3()

   def met4():
      print 'x'


 a = A()
 a.met1()
 >>> x
 a.met2()
 >>> AttributeError: A instance has no attribute 'met3'

Answer 2

Your error NameError: global name 'buildTool1' is not defined says you are trying to access the variable buildTool1 buts its not define in local or global.

Please check this

class test(object):

    def __init__(self, name):
        self.name = name

    def buildSimplex(self):
        print "CALL"

    def sA(self):
        self.buildSimplex()


if __name__ == '__main__':
    x = test('test')
    x.sA()