Access grandchild of a variable (parent.child.grandchild) without dots and one pair of brackets

Question

I'm building a canvas-related class with a kind of conversion table. The conversion table can be edited by the user. (Isn't really relevant, but maybe you want to know why):

cLayout = function(option) {
    //obtaining the canvas (el) here
    this.setup = function(option) {
        t=this.table;
        for (var p in t)
        {
            el[t[p][0]] = option[p]||t[p][1]
        }
    }
    this.setup(option)
}

cLayout.prototype.table = {
    width:[['style']['width'],"100%"],
    height:['style'['height'],"100%"],
    bg:[['style']['backgroundColor'],""],
    position:[['style']['position'],"absolute"],
    left:['style'['left'],"0px"],
    top:['style'['left'],"0px"]
}

Example:

var b = new cLayout({left:'10%',width:'90%'})

---

Real question:

Normally, I'd use el['style']['width'] to set el.style.width. But I want to use el[something] without the second pair of brackets: I want the property name to be completely variable (I also want to be able to set el['innerHTML']). So, is there a way to get a grandchild by using a[b], without using a[b][c]?

P.S. Of course, I don't want to use eval.

Answer 1

No it is not possible. If you have nested objects, you cannot just skip a level.

You could write a helper function though, which takes a string like "child.grandchild" and sets the corresponding property:

function setProp(obj, prop, val) {
    var parts = prop.split('.');
    while(parts.length > 1) {
        obj = obj[parts.shift()];
    }
    obj[parts.shift()] = val;
}

(You should also test whether a certain property is available.)

Then your code could look like:

var cLayout = function(option) {
    //obtaining the canvas (el) here
    this.setup = function(option) {
        for(var p in this.table) {
            setProp(el, this.table[p][0], option[p]||t[p][1]);
        }
    }
    this.setup(option)
}

cLayout.prototype.table = {
    width:['style.width',"100%"],
    height:['style.height',"100%"],
    //...
}