Question

I have a name of table or view in PostgreSQL database and need to delete in in single pgSQL command. How can i afford it?

I was able to select form system table to find out if there any table with such a name but stuck with procedural part:

SELECT count(*) FROM pg_tables where tablename='user_statistics';
Was it helpful?

Solution

DROP TABLE user_statistics;

DROP VIEW user_statistics;

complete syntax:

DROP TABLE

DROP VIEW

And if you want a complete function, i tried something like this:

CREATE OR REPLACE FUNCTION delete_table_or_view(objectName varchar) RETURNS integer AS $$
DECLARE
    isTable integer;
    isView integer;
BEGIN
    SELECT INTO isTable count(*) FROM pg_tables where tablename=objectName;
    SELECT INTO isView count(*) FROM pg_views where viewname=objectName;

    IF isTable = 1 THEN
        execute 'DROP TABLE ' || objectName;
        RETURN 1;
    END IF;

    IF isView = 1 THEN
        execute 'DROP VIEW ' || objectName;
        RETURN 2;
    END IF;

    RETURN 0;

END;
$$ LANGUAGE plpgsql;

OTHER TIPS

Consider using DROP TABLE IF EXISTS and DROP VIEW IF EXISTS. That way you won't get an error message if it fails, just a notice.

Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow
scroll top