Question about non-clustered index storage in SQL Server

Question

I have a table people with two non-clustered indexes.

create table people(
 id_person int,
 first_name varchar(50),
 last_name varchar(50),
 city varchar(100),
 state char(2),
 zip_code int
)

CREATE INDEX id_first_name_last_name ON people(first_name, last_name, id_person)
CREATE INDEX id_last_name_first_name ON people(id_person, last_name, first_name)

Each index refers to the same columns but in a different order.

-- Insert some rows

insert into people values(1,'joe','smith','new york', 'NY', 10701)
insert into people values(2,'john','smith','new york', 'NY', 10701)
insert into people values(3,'joyce','smith','new york', 'NY', 10701)
insert into people values(4,'jocelyn','smith','new york', 'NY', 10701)

The size of each index is as follows

TableName   IndexName            IndexID    Indexsize(KB)
people          NULL                     0           16
people          id_first_name_last_name  2           16
people          id_last_name_first_name  3           16

Each index is using 16KB.

Now if I add a clustered index on id_person

create clustered index ix_id_people on people(id_person)

I end up with the same amount of space being used by each index.

TableName   IndexName            IndexID    Indexsize(KB)
people          NULL                     1           16
people          id_first_name_last_name  2           16
people          id_last_name_first_name  3           16

The only difference is now instead of a HEAP, I have a clustered index.

I was expecting that with a clustered index on id_person, the storage engine wouldn't need to include id_person anymore in each non-clustered index.

Questions:

Are the values for each column referenced by a non-clustered index stored only for the first non-clustered index and then referenced by all additional non-clustered indexes?

If a non-clustered index references the clustered index column, are the values from that column copied physically onto each non-clustered index or just simply referenced?

Update 14:55

Here is the query being used to calculate index size

SELECT
OBJECT_NAME(i.OBJECT_ID) AS TableName,
i.name AS IndexName,
i.index_id AS IndexID,
8 * SUM(a.used_pages) AS 'Indexsize(KB)'
FROM sys.indexes AS i
JOIN sys.partitions AS p ON p.OBJECT_ID = i.OBJECT_ID AND p.index_id = i.index_id
JOIN sys.allocation_units AS a ON a.container_id = p.partition_id
GROUP BY i.OBJECT_ID,i.index_id,i.name
ORDER BY OBJECT_NAME(i.OBJECT_ID),i.index_id