Pass PHP Class as Parameter
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12-11-2019 - |
Question
How can i pass a class as a parameter in my function
So far i've tried
$sc = new SampleClass(); SampleFunction($sc); function SampleFunction(&$refClass) { echo $refClass->getValue(); }
this is a simplified example of what im doing.. i actually have to do complex procedures inside this sample function. I'm not getting any response from the sample function. What am i doing wrong? thank you
UPDATE
char.php
class Charss {
var $name=0;
var $hp=500;
var $spd=10;
var $rtime=10;
var $dmg=10;
function __construct( $name, $hp, $spd, $rtime , $dmg) {
$this->name = $name;
$this->hp = $hp;
$this->spd = $spd;
$this->rtime = $rtime;
$this->dmg = $dmg;
}
function get_name() {
return $this->name;
}
function set_name($new_name) {
$this->name = $new_name;
}
function get_hp() {
return $this->hp;
}
function set_hp($new_hp) {
$this->hp = $new_hp;
}
function get_spd() {
return $this->spd;
}
function set_spd($new_spd) {
$this->spd = $new_spd;
}
function get_rtime() {
return $this->rtime;
}
function set_rtime($new_rtime) {
$this->rtime = $new_rtime;
}
function get_dmg() {
return $this->get_dmg;
}
function set_dmg($new_dmg) {
$this->dmg = $new_dmg;
}
}
myclass.php
require("char.php");
class Person {
function try_process()
{
$chr1 = new Charss("Player1",500,3,0,50);
$chr2 = new Charss("Player2",500,6,0,70);
while ($chr1->get_hp() > 0 && $chr2->get_hp() > 0)
{
$sth = min($chr1->get_rtime(), $chr2->get_rtime());
if ($chr1->get_rtime() == 0 && $chr2->get_rtime() > 0)
{
exit;
Fight($chr1,$chr2);
$chr1->set_rtime($chr1->get_spd());
}
elseif ($chr2->get_rtime() == 0 && $chr1->get_rtime() > 0)
{
Fight($chr2,$chr1);
$chr2->set_rtime($chr2->get_spd());
}
else
{
Fight($chr1,$chr2); #having trouble with this
$chr1->set_rtime($chr1->get_spd());
}
$chr1->set_rtime($chr1->get_rtime() - $sth);
$chr2->set_rtime($chr2->get_rtime() - $sth);
}
}
function Fight($atk,$def)
{
$def->set_hp($def->get_hp() - $atk->get_dmg());
echo $atk->get_name() . " attacked " . $def->get_name() . " for " . $atk->get_dmg() . " damage";
}
}
so im calling the function try_process on button click
Solution
What you're actually doing there is passing an object, not a class.
$sc = new SampleClass();
creates an instance of SampleClass, aka an object.
I assume there's some error being thrown elsewhere as what you have is correct. I tested the following code and got the expected output:
class SampleClass
{
public function getValue()
{
return 4;
}
}
$sc = new SampleClass();
SampleFunction($sc);
function SampleFunction(&$refClass)
{
echo $refClass->getValue();
}
Output: 4
If you provide more details of your actual code we might be able to determine the problem.
OTHER TIPS
I can't see anything wrong with your code
using &$refClass is however is not recommended and I guess willbe removed from future iteration of PHP version
but here is an example
class objects are passed as reference I suppose so no need of '&'
Why is the function argument a reference? Probably shouldn't be.
Other than that, there's nothing wrong with you posted, so the error is likely within SampleClass
.
Others have answered pretty well, but this is a silly little example to show you how to modify the class (either by calling a property setter, or setting public properties directly)
class foo {
private $member1;
public $member2;
public function __construct($member1,$member2) {
$this->member1=$member1;
$this->member2=$member2;
}
public function SetMember1($value) {
$this->member1 = $value;
}
public function GetMember1() {
return $this->member1;
}
}
function SetMembers(foo $obj, $member1, $member2) {
// Call a setter
$obj->SetMember1($member1);
// Set a member variable directly
$obj->member2 = $member2;
}
$obj = new foo('default member 1', 'default member 2');
echo "member1 (before): {$obj->GetMember1()}\n";
echo "member2 (before): {$obj->member2}\n";
// Change values
SetMembers($obj, 'new member1', 'new member2');
echo "member1 (after): {$obj->GetMember1()}\n";
echo "member2 (after): {$obj->member2}\n";
This will output:
member1 (before): default member 1
member2 (before): default member 2
member1 (after): new member1
member2 (after): new member2