Doctrine 2 - How to use discriminator column in where clause
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13-11-2019 - |
Question
I was used discriminator column in where clause like this:
//f = root entity
$qb = $this->createQueryBuilder('f');
$qb->add('where', 'f.format = \'image\' OR f.format = \'text\'');
I've got an error: "Message: [Semantical Error] line 0, col 73 near 'format = 'image'': Error: Class Entities\File\AbstractFile has no field or association named format"
How can i use discriminator column in where clause?
Thanks.
Solution
I think that you should use INSTANCE OF
OTHER TIPS
It would look in query builder like this:
$class = 'Entity\File\Image';
$qb = $this->createQueryBuilder('f');
$qb->where($qb->expr()->isInstanceOf('f', $class));
Note: that you will not be able to set the class as a parameter because it will be escaped.
for PHP 5.50 and above:
$this->createQueryBuilder('f')
->andWhere('f INSTANCE OF '.Image::class)
As this latest doctrine version it is supported to query directly the discriminator value.
public function findOfType($discr)
{
$qb = $this->createQueryBuilder('e');
$qb->where('e INSTANCE OF :discr');
$qb->setParameter('discr', $discr);
return $qb->getQuery()->getResult();
}
will have a result query with this clause:
WHERE e0_.discr IN ('discriminator_passed_to_function')
This doctrine extension was very useful for me because I needed to access the parent class and INSTANCE OF
doesn't works in that case.
https://gist.github.com/jasonhofer/8420677
For example: I have the following class structure:
BaseClass
Class1 inherits from BaseClass (discriminator = c1)
Class2 inherits from Class1 (discriminator = c2)
Class3 inherits from Class1 (discriminator = c3)
I want to select all entities from Class1 but not from Class2 or Class3
SELECT c FROM \Class1 c WHERE TYPE(c) = 'c1';