UIImageView showing UIPopOver

Question

I would like to fire up this event:

- (IBAction)profilePop:(id)sender
{
    ProfileViewController * profile = [[ProfileViewController alloc] init];
    UIImageView * temp = ((UIImageView *)sender);
    profile.uid =  [[[posts objectAtIndex:((UIImageView *)sender).tag] creator] mid];
    NSLog(@"profile id %@", profile.uid);
    UIPopoverController * profilePop  = [[UIPopoverController alloc] initWithContentViewController:profile];
    [profilePop presentPopoverFromRect:CGRectMake(temp.frame.origin.x+temp.frame.size.width, temp.frame.origin.y + temp.frame.size.height/2, profile.view.frame.size.width, profile.view.frame.size.height) inView:self.view permittedArrowDirections:UIPopoverArrowDirectionRight animated:YES];
}

when a user taps on an UIImageView. All I am trying to do is to show a popover when an UIImageView is clicked and it is shown to the right of the UIImageView. I see that UIImageView doesn't have an addAction attribute from it as it's not a subclass of UIControl. I did some research that I might probably have to use a UIButton instead. Is this true? Is there a way to do this using UIImageView so I don't have to rewrite the code again? I

Answer 1

First.

you could get the touch on any object, which has super class as UIView.

if you see the UIImageView in apple documentation.

UIView : UIResponder : NSObject

UIResponder has function to get the touches. So implement the below functions in your view class and detect the touches on your UIImageView .

– touchesBegan:withEvent:
– touchesMoved:withEvent:
– touchesEnded:withEvent:
– touchesCancelled:withEvent:

Second:

you could also create the UITapGestureRecognizer for UIImageView.

Check the below blog tutorial.

Working with UIGestureRecognizers

EDITED:

Use below code :

UITapGestureRecognizer *tapRecognizer = [[UITapGestureRecognizer alloc]             initWithTarget:self action:@selector(tapped:)];
[tapRecognizer setNumberOfTapsRequired:1];
[tapRecognizer setDelegate:self];
[MyImageView addGestureRecognizer:tapRecognizer];

if user tap once, tapped function will be called , So you tabbed function implemntation should be look like below

 -(void)tapped:(id)sender
     {

       NSLog(@"See a tap gesture");

         ProfileViewController * profile = [[ProfileViewController alloc] init];
         UIImageView * temp = [(UIPanGestureRecognizer*)sender view];
        profile.uid =  [[[posts objectAtIndex:((UIImageView *)sender).tag] creator] mid];
        NSLog(@"profile id %@", profile.uid);
        UIPopoverController * profilePop  = [[UIPopoverController alloc] initWithContentViewController:profile];
      [profilePop presentPopoverFromRect:CGRectMake(temp.frame.origin.x+temp.frame.size.width, temp.frame.origin.y + temp.frame.size.height/2, profile.view.frame.size.width, profile.view.frame.size.height) inView:self.view permittedArrowDirections:UIPopoverArrowDirectionRight animated:YES];
    }

Answer 2

What about using an UIButton instead and using the class method to add your UIImage to it.

- (void)setImage:(UIImage *)image forState:(UIControlState)state 

Answer 3

You can define a UIButton of type custom, don't give it any text or image, give it a clear background, and the same frame as your image view. Then add your target/selector to the button and it will appear to the user they are tapping the image view, when they are actually tapping an invisible button. This should take about 3 minutes to set up in IB, so I don't think you'll need to rewrite your code again.

Answer 4

You could create a Tap Gesture recognizer and attach it to the UIImageView.

// By now imageView exists!
UITapGestureRecognizer *tapGesture = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleTapGesture:)];
tapGesture.numberOfTapsRequired = 1;
tapGesture.numberOfTouchesRequired = 1;
[imageView addGestureRecognizer:tapGesture];
[tapGesture release];

Now the handleTapGesture will be quite similar to your -profilePop:

Since you are talking of pop over controllers, I assume you already have gesture recognizers available.