Why does the this arithmetic equal 10 and not 0 with a mod in Java

Question

I'm working on an old exam for a test and this code is printing the value of 10 for longVariable. Now, by hand, to me, the math would go 9 + 1 % 10 = remainder of 0, not 10... How am I wrong on this?

Thank you for helping!

 public class ExamSectionA
{
    public static void main(String[] args)
{
    int intVariable1 = 9;
    int intVariable2 = 10;
    double doubleVariable = 11.2;
    char charVariable = 'A';
    long longVariable;
    longVariable = intVariable1 + 1 % intVariable2;
    intVariable2 = (int) (doubleVariable / 10f);
    String[] theirSalary = {"10","20","30","40"};
    System.out.println(intVariable2);
    System.out.println(longVariable); 
}
}

EDIT: PEMDAS. Think I got it.

Answer 1

Watch your order of operations:

intVariable1 + 1 % intVariable2;

is:

intVariable1 + (1 % intVariable2);

So 9 + 1 % 10 is being parsed as 9 + (1 % 10). Which gives 9 + 1 = 10.

% has higher precedence than +.

Answer 2

% operator has higher priority than +. For more information go here

Corrected code: (intVariable1 + 1) % intVariable2;

Answer 3

Did you mean instead (9+1) % 10 ?