Question

I'm developing an iPhone app. In a label, I want to show an user's first letter of the name uppercase. How do I do that?

Was it helpful?

Solution

If there is only one word String, then use the method

-capitalized

let capitalizedString = myStr.capitalized // capitalizes every word

Otherwise, for multi word strings, you have to extract first character and make only that character upper case.

OTHER TIPS

(2014-07-24: Currently accepted answer is not correct) The question is very specific: Make the first letter uppercase, leave the rest lowercase. Using capitalizedString produces a different result: “Capitalized String” instead of “Capitalized string”. There is another variant depending on the locale, which is capitalizedStringWithLocale, but it's not correct for spanish, right now it's using the same rules as in english, so this is how I'm doing it for spanish:

NSString *abc = @"this is test";

abc = [NSString stringWithFormat:@"%@%@",[[abc substringToIndex:1] uppercaseString],[abc substringFromIndex:1] ];       
NSLog(@"abc = %@",abc);

In case someone is still interested in 2016, here is a Swift 3 extension:

extension String {
    func capitalizedFirst() -> String {
        let first = self[self.startIndex ..< self.index(startIndex, offsetBy: 1)]
        let rest = self[self.index(startIndex, offsetBy: 1) ..< self.endIndex]
        return first.uppercased() + rest.lowercased()
    }

    func capitalizedFirst(with: Locale?) -> String {
        let first = self[self.startIndex ..< self.index(startIndex, offsetBy: 1)]
        let rest = self[self.index(startIndex, offsetBy: 1) ..< self.endIndex]
        return first.uppercased(with: with) + rest.lowercased(with: with)
    }
}

Then you use it exactly as you would for the usual uppercased() or capitalized():

myString.capitalizedFirst() or myString.capitalizedFirst(with: Locale.current)

Simply

- (NSString *)capitalizeFirstLetterOnlyOfString:(NSString *)string{
     NSMutableString *result = [string lowercaseString].mutableCopy;
     [result replaceCharactersInRange:NSMakeRange(0, 1) withString:[[result substringToIndex:1] capitalizedString]];

     return result;
}

This is for your NSString+Util category...

- (NSString *) capitalizedFirstLetter {
    NSString *retVal;
    if (self.length < 2) {
        retVal = self.capitalizedString;
    } else {
        retVal = string(@"%@%@",[[self substringToIndex:1] uppercaseString],[self substringFromIndex:1]);
    }
    return retVal;
}

You can do that with NSString stringWithFormat, of course. I use this weirdness:

#define string(...) \
[NSString stringWithFormat:__VA_ARGS__]

here's a swift extension for it

extension NSString {
    func capitalizeFirstLetter() -> NSString {
        return self.length > 1 ?
          self.substringToIndex(1).capitalizedString + self.substringFromIndex(1) :
          self.capitalizedString
    }
}

This is how it worked for me:

NSString *serverString = jsonObject[@"info"];

NSMutableString *textToDisplay = [NSMutableString stringWithFormat:@"%@", serverString];

[textToDisplay replaceCharactersInRange:NSMakeRange(0, 1) withString:[textToDisplay substringToIndex:1].capitalizedString];

cell.infoLabel.text = textToDisplay;

Hope it helps.

As an extension to the accepted answer

capitalizedString is used for making uppercase letters .

NSString *capitalizedString = [myStr capitalizedString]; // capitalizes every word

But if you have many words in a string and wants to get only first character as upper case use the below solution

NSString *firstCapitalChar = [[string substringToIndex:1] capitalizedString];
NSString *capString = [string stringByReplacingCharactersInRange:NSMakeRange(0,1) withString: capString];


// extract first character and make only that character upper case.

Swift:

let userName = "hard CODE"
yourLabel.text = userName.localizedUppercaseString

I recommend using this localised version of uppercase, since names are locale sensitive.

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