error faced while working on jsp and mysql

StackOverflow https://stackoverflow.com/questions/9035992

  •  03-12-2019
  •  | 
  •  

Question

while creating a login jsp page i m getting this error when the username and password is entered and clicked submitted...

org.apache.jasper.JasperException: /loginbean.jsp (line: 9, column: 57) Attribute value request.getParameter("userName") is quoted with " which must be escaped when used within the value
org.apache.jasper.compiler.DefaultErrorHandler.jspError(DefaultErrorHandler.java:42)
org.apache.jasper.compiler.ErrorDispatcher.dispatch(ErrorDispatcher.java:408)
org.apache.jasper.compiler.ErrorDispatcher.jspError(ErrorDispatcher.java:89)
org.apache.jasper.compiler.Parser.parseAttributeValue(Parser.java:280)
org.apache.jasper.compiler.Parser.parseAttribute(Parser.java:229)
org.apache.jasper.compiler.Parser.parseAttributes(Parser.java:162)
org.apache.jasper.compiler.Parser.parseAttributes(Parser.java:153)
org.apache.jasper.compiler.Parser.parseSetProperty(Parser.java:913)
org.apache.jasper.compiler.Parser.parseStandardAction(Parser.java:1134)
org.apache.jasper.compiler.Parser.parseElements(Parser.java:1451)
org.apache.jasper.compiler.Parser.parseBody(Parser.java:1664)
org.apache.jasper.compiler.Parser.parseOptionalBody(Parser.java:1002)
org.apache.jasper.compiler.Parser.parseUseBean(Parser.java:958)
org.apache.jasper.compiler.Parser.parseStandardAction(Parser.java:1136)
org.apache.jasper.compiler.Parser.parseElements(Parser.java:1451)
org.apache.jasper.compiler.Parser.parse(Parser.java:138)
org.apache.jasper.compiler.ParserController.doParse(ParserController.java:242)
org.apache.jasper.compiler.ParserController.parse(ParserController.java:102)
org.apache.jasper.compiler.Compiler.generateJava(Compiler.java:198)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:373)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:353)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:340)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:646)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:357)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:722)

Update 1

JSP Code used is

<jsp:useBean id="db" scope="request" class="logbean.LoginBean" >

<jsp:setProperty name="db" property="userName" value="%=request.getParameter("userName")%>"/>

<jsp:setProperty name="db" property="password" value="%=request.getParameter("password")%>"/>

</jsp:useBean>

Was it helpful?

Solution

You are missing a brace in your scriptlet tags:

<jsp:setProperty name="db" property="userName" value="%=request.getParameter("userName")%>"/>
<jsp:setProperty name="db" property="password" value="%=request.getParameter("password")%>"/>

Should be:

<jsp:setProperty name="db" property="userName" value="<%=request.getParameter("userName")%>"/>
<jsp:setProperty name="db" property="password" value="<%=request.getParameter("password")%>"/>

However, I would recommend against using scriptlets in general. You can bypass the use of setting properties like this, and can access the objects by using the implicit param object with JSTL. This of course depends on what the rest of your JSP is doing, but it's considered best practice.

For example:

User name is: <c:out value="${param.userName}" />
Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow
scroll top