Removing carriage return and new-line from the end of a string in c#

Question

How do I remove the carriage return character (\r) and the new line character(\n) from the end of a string?

Answer 1

This will trim off any combination of carriage returns and newlines from the end of s:

s = s.TrimEnd(new char[] { '\r', '\n' });

Edit: Or as JP kindly points out, you can spell that more succinctly as:

s = s.TrimEnd('\r', '\n');

Answer 2

This should work ...

var tst = "12345\n\n\r\n\r\r";
var res = tst.TrimEnd( '\r', '\n' );

Answer 3

If you are using multiple platforms you are safer using this method.

value.TrimEnd(System.Environment.NewLine.ToCharArray());

It will account for different newline and carriage-return characters.

Answer 4

String temp = s.replace("\r\n","").trim();

s being the original string.

Answer 5

s.TrimEnd();

The above is all I needed to remove '\r\n' from the end of my string.

The upvoted answer seems wrong to me. Firstly, it didn't work when I tried, secondly, if it did work I would expect that s.TrimEnd('\r', '\n') would only remove either a '\r' or a '\n', so I'd have to run it over my string twice - once for when '\n' was at the end and the second time for when '\r' was at the end (now that the '\n' was removed).

Answer 6

If there's always a single CRLF, then:

myString = myString.Substring(0, myString.Length - 2);

If it may or may not have it, then:

Regex re = new Regex("\r\n$");
re.Replace(myString, "");

Both of these (by design), will remove at most a single CRLF. Cache the regex for performance.

Answer 7

For us VBers:

TrimEnd(New Char() {ControlChars.Cr, ControlChars.Lf})

Answer 8

string k = "This is my\r\nugly string. I want\r\nto change this. Please \r\n help!";
k = System.Text.RegularExpressions.Regex.Replace(k, @"\r\n+", " ");

Answer 9

This was too easy -- for me I'm filtering out certain email items. I'm writing my own custom email junk filter. With \r and/or \n in the string it was wiping out all items instead of filtering.

So, I just did filter = filter.Remove('\n') and filter = filter.Remove('\r'). I'm making my filter such that an end user can use Notepad to directly edit the file so there's no telling where these characters might embed themselves -- could be other than at the start or end of the string. So removing them all does it.

The other entries all work but Remove might be the easiest?

I learned quite a bit more about Regex from this post -- pretty cool work with its use here.

Answer 10

I use lots of erasing level

String donen = "lots of stupid whitespaces and new lines and others..."

//Remove multilines
donen = Regex.Replace(donen, @"^\s+$[\r\n]*", "", RegexOptions.Multiline);
//remove multi whitespaces
RegexOptions options = RegexOptions.None;
Regex regex = new Regex("[ ]{2,}", options);
donen = regex.Replace(donen, " ");
//remove tabs
char tab = '\u0009';
donen = donen.Replace(tab.ToString(), "");
//remove endoffile newlines
donen = donen.TrimEnd('\r', '\n');
//to be sure erase new lines again from another perspective
donen.Replace(Environment.NewLine, "");

and now we have a clean one row

Answer 11

varName.replace(/[\r\n]/mg, '')