Question

Possible Duplicate:
Yield In VB.NET

In C#, when writing a function that returns an IEnumerble<>, you can use yield return to return a single item of the enumeration and yield break; to signify no remaining items. What is the VB.NET syntax for doing the same thing?

An example from the NerdDinner code:

public IEnumerable<RuleViolation> GetRuleViolations() {

   if (String.IsNullOrEmpty(Title))
       yield return new RuleViolation("Title required","Title");

   if (String.IsNullOrEmpty(Description))
       yield return new RuleViolation("Description required","Description");

   if (String.IsNullOrEmpty(HostedBy))
       yield return new RuleViolation("HostedBy required", "HostedBy");

   if (String.IsNullOrEmpty(Address))
       yield return new RuleViolation("Address required", "Address");

   if (String.IsNullOrEmpty(Country))
       yield return new RuleViolation("Country required", "Country");

   if (String.IsNullOrEmpty(ContactPhone))
       yield return new RuleViolation("Phone# required", "ContactPhone");

   if (!PhoneValidator.IsValidNumber(ContactPhone, Country))
       yield return new RuleViolation("Phone# does not match country", "ContactPhone");

   yield break;
}

This convert C# to VB.NET tool gives a "YieldStatement is unsupported" error.

Was it helpful?

Solution

There is currently no equivalent to C#'s yield return in VB.Net from a language syntax level.

However there was a recent write up in MSDN magazine by Bill McCarthy on how to implement a similar pattern in VB.Net 9.0

OTHER TIPS

The new Async CTP includes support for Yield in VB.NET.

See Iterators in Visual Basic for information on usage.

See my answers here:

To summarize:
VB.Net does not have yield, but C# implements yield by converting your code to a state machine behind that scenes. VB.Net's Static keyword also allows you to store state within a function, so in theory you should be able to implement a class that allows you to write similar code when used as a Static member of a method.

No yield return in VB.NET :( Just create a list and return it.

Behind the scenes, the compiler creates an enumerator class to do the work. Since VB.NET does not implement this pattern, you have to create your own implementation of IEnumerator(Of T)

Below gives output: 2, 4, 8, 16, 32

In VB,

Public Shared Function setofNumbers() As Integer()

    Dim counter As Integer = 0
    Dim results As New List(Of Integer)
    Dim result As Integer = 1
    While counter < 5
        result = result * 2
        results.Add(result)
        counter += 1
    End While
    Return results.ToArray()
End Function

Private Sub Form1_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
    For Each i As Integer In setofNumbers()
        MessageBox.Show(i)
    Next
End Sub

In C#

   private void Form1_Load(object sender, EventArgs e)
    {
        foreach (int i in setofNumbers())
        {
            MessageBox.Show(i.ToString());
        }
    }

    public static IEnumerable<int> setofNumbers()
    {
        int counter=0;
        //List<int> results = new List<int>();
        int result=1;
        while (counter < 5)
        {
          result = result * 2;
          counter += 1;
          yield return result;
        }
    }
Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow
scroll top