Python sort dictionary items by value then by key

Question

I have the following dictionary:

{1: (8, 3), 0: (8, 0), 2: (2, 3), 3: (2, 0)}

I would like to sort it by the tuple key and then by the key of the dictionary so the above will be:

 [{1: (2, 3), 3: (2, 0),0: (8, 3), 1: (8, 0)}]

I wrote the following:

result_list = sorted(codebook.items(), key= lambda item: item[1][0])

This sort by the tuple key but not afterwards by the dictionary key.

How can I do it?

Answer 1

sorted(codebook.items(), key= lambda item: (item[1][0],item[0]))

this will sort first by the first item in the tuple then by the dictionary key

just to clarify a few things for OP

• Dictionaries are not sortable, so you cannot ever have a "sorted" dictionary

  • (there is a OrderedDictionary, but its essentially the same as a NamedTuple, both of these containers do have an order)

• This will return a list of tuples not a dictionary. the return will look like

  [(dictionary_key,(tuple,values)),(dictionary_key,(tuple,values),...]