How to enumerate an enum with String type?

Question

enum Suit: String {
    case spades = "♠"
    case hearts = "♥"
    case diamonds = "♦"
    case clubs = "♣"
}

For example, how can I do something like:

for suit in Suit {
    // do something with suit
    print(suit.rawValue)
}

Resulting example:

♠
♥
♦
♣

Answer 1

Swift 4.2+

Starting with Swift 4.2 (with Xcode 10), just add protocol conformance to CaseIterable to benefit from allCases:

extension Suit: CaseIterable {}

Then this will print all possible values:

Suit.allCases.forEach {
    print($0.rawValue)
}

Compatibility with earlier Swift versions (3.x and 4.x)

Just mimic the Swift 4.2 implementation:

#if !swift(>=4.2)
public protocol CaseIterable {
    associatedtype AllCases: Collection where AllCases.Element == Self
    static var allCases: AllCases { get }
}
extension CaseIterable where Self: Hashable {
    static var allCases: [Self] {
        return [Self](AnySequence { () -> AnyIterator<Self> in
            var raw = 0
            var first: Self?
            return AnyIterator {
                let current = withUnsafeBytes(of: &raw) { $0.load(as: Self.self) }
                if raw == 0 {
                    first = current
                } else if current == first {
                    return nil
                }
                raw += 1
                return current
            }
        })
    }
}
#endif

Answer 2

This post is relevant here https://www.swift-studies.com/blog/2014/6/10/enumerating-enums-in-swift

Essentially the proposed solution is

enum ProductCategory : String {
     case Washers = "washers", Dryers = "dryers", Toasters = "toasters"

     static let allValues = [Washers, Dryers, Toasters]
}

for category in ProductCategory.allValues{
     //Do something
}

Answer 3

I made a utility function iterateEnum() for iterating cases for arbitrary enum types.

Here is the example usage:

enum Suit: String {
    case Spades = "♠"
    case Hearts = "♥"
    case Diamonds = "♦"
    case Clubs = "♣"
}

for f in iterateEnum(Suit) {
    println(f.rawValue)
}

outputs:

♠
♥
♦
♣

But, this is only for debug or test purpose: This relies on several undocumented current(Swift1.1) compiler behaviors. So, use it at your own risk.

Here is the code:

func iterateEnum<T: Hashable>(_: T.Type) -> GeneratorOf<T> {
    var cast: (Int -> T)!
    switch sizeof(T) {
        case 0: return GeneratorOf(GeneratorOfOne(unsafeBitCast((), T.self)))
        case 1: cast = { unsafeBitCast(UInt8(truncatingBitPattern: $0), T.self) }
        case 2: cast = { unsafeBitCast(UInt16(truncatingBitPattern: $0), T.self) }
        case 4: cast = { unsafeBitCast(UInt32(truncatingBitPattern: $0), T.self) }
        case 8: cast = { unsafeBitCast(UInt64($0), T.self) }
        default: fatalError("cannot be here")
    }

    var i = 0
    return GeneratorOf {
        let next = cast(i)
        return next.hashValue == i++ ? next : nil
    }
}

The underlying idea is:

• Memory representation of enum - excluding enums with associated types - is just an index of cases when the count of the cases is 2...256, it's identical to UInt8, when 257...65536, it's UInt16 and so on. So, it can be unsafeBitcast from corresponding unsigned integer types.
• .hashValue of enum values is the same as the index of the case.
• .hashValue of enum values bitcasted from invalid index is 0

---

ADDED:

Revised for Swift2 and implemented casting ideas from @Kametrixom's answer

func iterateEnum<T: Hashable>(_: T.Type) -> AnyGenerator<T> {
    var i = 0
    return anyGenerator {
        let next = withUnsafePointer(&i) { UnsafePointer<T>($0).memory }
        return next.hashValue == i++ ? next : nil
    }
}

---

ADDED: Revised for Swift3

func iterateEnum<T: Hashable>(_: T.Type) -> AnyIterator<T> {
    var i = 0
    return AnyIterator {
        let next = withUnsafePointer(to: &i) {
            $0.withMemoryRebound(to: T.self, capacity: 1) { $0.pointee }
        }
        if next.hashValue != i { return nil }
        i += 1
        return next
    }
}

---

ADDED: Revised for Swift3.0.1

func iterateEnum<T: Hashable>(_: T.Type) -> AnyIterator<T> {
    var i = 0
    return AnyIterator {
        let next = withUnsafeBytes(of: &i) { $0.load(as: T.self) }
        if next.hashValue != i { return nil }
        i += 1
        return next
    }
}

Answer 4

The other solutions work but they all make assumptions of for example the number of possible ranks and suits, or what the first and last rank may be. True, the layout of a deck of cards probably isn't going to change much in the foreseeable future. In general, however, it's neater to write code which makes as little assumptions as possible. My solution:

I've added a raw type to the Suit enum, so I can use Suit(rawValue:) to access the Suit cases:

enum Suit: Int {
    case Spades = 1
    case Hearts, Diamonds, Clubs
    func simpleDescription() -> String {
        switch self {
            case .Spades:
                return "spades"
            case .Hearts:
                return "hearts"
            case .Diamonds:
                return "diamonds"
            case .Clubs:
                return "clubs"
        }
    }
    func color() -> String {
        switch self {
        case .Spades:
            return "black"
        case .Clubs:
            return "black"
        case .Diamonds:
            return "red"
        case .Hearts:
            return "red"
        }
    }
}

enum Rank: Int {
    case Ace = 1
    case Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten
    case Jack, Queen, King
    func simpleDescription() -> String {
        switch self {
            case .Ace:
                return "ace"
            case .Jack:
                return "jack"
            case .Queen:
                return "queen"
            case .King:
                return "king"
            default:
                return String(self.rawValue)
        }
    }
}

Below the implementation of Card's createDeck() method. init(rawValue:) is a failable initializer and returns an optional. By unwrapping and checking its value in both while statements, there's no need to assume the number of Rank or Suit cases:

struct Card {
    var rank: Rank
    var suit: Suit
    func simpleDescription() -> String {
        return "The \(rank.simpleDescription()) of \(suit.simpleDescription())"
    }
    func createDeck() -> [Card] {
        var n = 1
        var deck = [Card]()
        while let rank = Rank(rawValue: n) {
            var m = 1
            while let suit = Suit(rawValue: m) {
                deck.append(Card(rank: rank, suit: suit))
                m += 1
            }
            n += 1
        }
        return deck
    }
}

Here is how to call the createDeck method:

let card = Card(rank: Rank.Ace, suit: Suit.Clubs)
let deck = card.createDeck()

Answer 5

The second answer that really works

So I stumbled around in the bits and bytes and created an extension (that I later found out works very similar to @rintaro's answer). It's usable like this:

enum E : EnumCollection {
    case A, B, C
}

Array(E.cases())    // [A, B, C]

Remarkable is that it's usable on any enum (without associated values). Note that this doesn't work for enums that have no cases.

Disclaimer

As with @rintaro's answer, this code uses the underlying representation of an enum. This representation isn't documented and might change in the future, which would break it -> I don't recommend the usage of this in production.

Code (Swift 2.2, Xcode 7.3.1, not working on Xcode 10)

protocol EnumCollection : Hashable {}
extension EnumCollection {
    static func cases() -> AnySequence<Self> {
        typealias S = Self
        return AnySequence { () -> AnyGenerator<S> in
            var raw = 0
            return AnyGenerator {
                let current : Self = withUnsafePointer(&raw) { UnsafePointer($0).memory }
                guard current.hashValue == raw else { return nil }
                raw += 1
                return current
            }
        }
    }
}

Code (Swift 3, Xcode 8.1, not working on Xcode 10)

protocol EnumCollection : Hashable {}
extension EnumCollection {
    static func cases() -> AnySequence<Self> {
        typealias S = Self
        return AnySequence { () -> AnyIterator<S> in
            var raw = 0
            return AnyIterator {
                let current : Self = withUnsafePointer(to: &raw) { $0.withMemoryRebound(to: S.self, capacity: 1) { $0.pointee } }
                guard current.hashValue == raw else { return nil }
                raw += 1
                return current
            }
        }
    }
}

(I have no idea why I need the typealias, but the compiler complains without it)

(I made big modification to this answer, look at edits for past versions)

Answer 6

You could iterate through an enum by implementing the ForwardIndexType protocol.

The ForwardIndexType protocol requires you to define a successor() function to step through the elements.

enum Rank: Int, ForwardIndexType {
    case Ace = 1
    case Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten
    case Jack, Queen, King

    // ... other functions

    // Option 1 - Figure it out by hand
    func successor() -> Rank {
        switch self {
            case .Ace:
              return .Two
            case .Two:
              return .Three

            // ... etc.

            default:
              return .King
        }
    }

    // Option 2 - Define an operator!
    func successor() -> Rank {
        return self + 1
    }
}

// NOTE: The operator is defined OUTSIDE the class
func + (left: Rank, right: Int) -> Rank {
    // I'm using to/from raw here, but again, you can use a case statement
    // or whatever else you can think of

    return left == .King ? .King : Rank(rawValue: left.rawValue + right)!
}

Iterating over an open or closed range (..< or ...) will internally call the successor() function which allows you to write this:

// Under the covers, successor(Rank.King) and successor(Rank.Ace) are called to establish limits
for r in Rank.Ace...Rank.King {
    // Do something useful
}

Answer 7

This problem is now much easier. Here is my Swift 4.2 Solution.

enum Suit: Int, CaseIterable {
    case None
    case Spade, Heart, Diamond, Club

    static let allNonNullCases = Suit.allCases[Spade.rawValue...]
}

enum Rank: Int, CaseIterable {
    case Joker
    case Two, Three, Four, Five, Six, Seven, Eight
    case Nine, Ten, Jack, Queen, King, Ace

    static let allNonNullCases = Rank.allCases[Two.rawValue...]
}

func makeDeck(withJoker: Bool = false) -> [Card] {
    var deck = [Card]()
    for suit in Suit.allNonNullCases {
        for rank in Rank.allNonNullCases {
            deck.append(Card(suit: suit, rank: rank))
        }
    }
    if withJoker {
        deck.append(Card(suit: .None, rank: .Joker))
    }
    return deck
}

Pre 4.2

I like this solution which I put together after finding this page: List comprehension in Swift

It uses Int raws instead of Strings but it avoids typing twice, it allows customizing the ranges, and doesn't hard code raw values.

This is Swift 4 Version of my original solution but see the 4.2 improvement above.

enum Suit: Int {
    case None
    case Spade, Heart, Diamond, Club

    static let allRawValues = Suit.Spade.rawValue...Suit.Club.rawValue
    static let allCases = Array(allRawValues.map{ Suit(rawValue: $0)! })
}
enum Rank: Int {
    case Joker
    case Two, Three, Four, Five, Six
    case Seven, Eight, Nine, Ten
    case Jack, Queen, King, Ace

    static let allRawValues = Rank.Two.rawValue...Rank.Ace.rawValue
    static let allCases = Array(allRawValues.map{ Rank(rawValue: $0)! })
}
func makeDeck(withJoker: Bool = false) -> [Card] {
    var deck = [Card]()
    for suit in Suit.allCases {
        for rank in Rank.allCases {
            deck.append(Card(suit: suit, rank: rank))
        }
    }
    if withJoker {
        deck.append(Card(suit: .None, rank: .Joker))
    }
    return deck
}

Answer 8

In principle it is possible to do it this way assuming that you don't use raw values assignment for enum's cases:

enum RankEnum: Int {
  case Ace
  case One
  case Two
}

class RankEnumGenerator: Generator {
    var i = 0
    typealias Element = RankEnum
    func next() -> Element? {
        let r = RankEnum.fromRaw(i)
        i += 1
        return r
    }
}

extension RankEnum {
    static func enumerate() -> SequenceOf<RankEnum> {
        return SequenceOf<RankEnum>({ RankEnumGenerator() })
    }
}

for r in RankEnum.enumerate() {
    println("\(r.toRaw())")
}

Answer 9

If you give the enum a raw Int value it will make looping much easier.

For example, you can use anyGenerator to get a generator that can enumerate across your values:

enum Suit: Int, CustomStringConvertible {
    case Spades, Hearts, Diamonds, Clubs
    var description: String {
        switch self {
        case .Spades:   return "Spades"
        case .Hearts:   return "Hearts"
        case .Diamonds: return "Diamonds"
        case .Clubs:    return "Clubs"
        }
    }
    static func enumerate() -> AnyGenerator<Suit> {
        var nextIndex = Spades.rawValue
        return anyGenerator { Suit(rawValue: nextIndex++) }
    }
}
// You can now use it like this:
for suit in Suit.enumerate() {
    suit.description
}
// or like this:
let allSuits: [Suit] = Array(Suit.enumerate())

---

However, this looks like a fairly common pattern, wouldn't it be nice if we could make any enum type enumerable by simply conforming to a protocol? Well with Swift 2.0 and protocol extensions, now we can!

Simply add this to your project:

protocol EnumerableEnum {
    init?(rawValue: Int)
    static func firstValue() -> Int
}
extension EnumerableEnum {
    static func enumerate() -> AnyGenerator<Self> {
        var nextIndex = firstRawValue()
        return anyGenerator { Self(rawValue: nextIndex++) }
    }
    static func firstRawValue() -> Int { return 0 }
}

Now any time you create an enum (so long as it has an Int raw value), you can make it enumerable by conforming to the protocol:

enum Rank: Int, EnumerableEnum {
    case Ace, Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King
}
// ...
for rank in Rank.enumerate() { ... }

If your enum values don't start with 0 (the default), override the firstRawValue method:

enum DeckColor: Int, EnumerableEnum {
    case Red = 10, Blue, Black
    static func firstRawValue() -> Int { return Red.rawValue }
}
// ...
let colors = Array(DeckColor.enumerate())

---

The final Suit class, including replacing simpleDescription with the more standard CustomStringConvertible protocol, will look like this:

enum Suit: Int, CustomStringConvertible, EnumerableEnum {
    case Spades, Hearts, Diamonds, Clubs
    var description: String {
        switch self {
        case .Spades:   return "Spades"
        case .Hearts:   return "Hearts"
        case .Diamonds: return "Diamonds"
        case .Clubs:    return "Clubs"
        }
    }
}
// ...
for suit in Suit.enumerate() {
    print(suit.description)
}

---

EDIT:

Swift 3 syntax:

protocol EnumerableEnum {
    init?(rawValue: Int)
    static func firstRawValue() -> Int
}

extension EnumerableEnum {
    static func enumerate() -> AnyIterator<Self> {
        var nextIndex = firstRawValue()

        let iterator: AnyIterator<Self> = AnyIterator {
            defer { nextIndex = nextIndex + 1 }
            return Self(rawValue: nextIndex)
        }

        return iterator
    }

    static func firstRawValue() -> Int {
        return 0
    }
}

Answer 10

Updated to Swift 2.2+

func iterateEnum<T: Hashable>(_: T.Type) -> AnyGenerator<T> {
    var i = 0
    return AnyGenerator {
        let next = withUnsafePointer(&i) {
            UnsafePointer<T>($0).memory
        }
        if next.hashValue == i {
            i += 1
            return next
        } else {
            return nil
        }
    }
}

It's updated code to Swift 2.2 form @Kametrixom's answer

For Swift 3.0+ (many thanks to @Philip)

func iterateEnum<T: Hashable>(_: T.Type) -> AnyIterator<T> {
    var i = 0
    return AnyIterator {
        let next = withUnsafePointer(&i) {
            UnsafePointer<T>($0).pointee
        }
        if next.hashValue == i {
            i += 1
            return next
        } else {
            return nil
        }
    }
}

Answer 11

I found myself doing .allValues alot throughout my code. I finally figured out a way to simply conform to an Iteratable protocol and have an rawValues() method.

protocol Iteratable {}
extension RawRepresentable where Self: RawRepresentable {

    static func iterateEnum<T: Hashable>(_: T.Type) -> AnyIterator<T> {
        var i = 0
        return AnyIterator {
            let next = withUnsafePointer(to: &i) {
                $0.withMemoryRebound(to: T.self, capacity: 1) { $0.pointee }
            }
            if next.hashValue != i { return nil }
            i += 1
            return next
        }
    }
}

extension Iteratable where Self: RawRepresentable, Self: Hashable {
    static func hashValues() -> AnyIterator<Self> {
        return iterateEnum(self)
    }

    static func rawValues() -> [Self.RawValue] {
        return hashValues().map({$0.rawValue})
    }
}


// Example
enum Grocery: String, Iteratable {
    case Kroger = "kroger"
    case HEB = "h.e.b."
    case Randalls = "randalls"
}

let groceryHashes = Grocery.hashValues() // AnyIterator<Grocery>
let groceryRawValues = Grocery.rawValues() // ["kroger", "h.e.b.", "randalls"]

Answer 12

Xcode 10 with Swift 4.2

enum Filter: String, CaseIterable {

    case salary = "Salary"
    case experience = "Experience"
    case technology = "Technology"
    case unutilized = "Unutilized"
    case unutilizedHV = "Unutilized High Value"

    static let allValues = Filter.allCases.map { $0.rawValue }
}

Call it

print(Filter.allValues)

Prints:

["Salary", "Experience", "Technology", "Unutilized", "Unutilized High Value"]

---

Older versions

For enum representing Int

enum Filter: Int {
    case salary
    case experience
    case technology
    case unutilized
    case unutilizedHV

    static let allRawValues = salary.rawValue...unutilizedHV.rawValue  // First to last case
    static let allValues = allRawValues.map { Filter(rawValue: $0)!.rawValue }
}

Call it like this:

print(Filter.allValues)

Prints:

[0, 1, 2, 3, 4]

---

For enum representing String

enum Filter: Int {
    case salary
    case experience
    case technology
    case unutilized
    case unutilizedHV

    static let allRawValues = salary.rawValue...unutilizedHV.rawValue  // First to last case
    static let allValues = allRawValues.map { Filter(rawValue: $0)!.description }
}

extension Filter: CustomStringConvertible {
    var description: String {
        switch self {
        case .salary: return "Salary"
        case .experience: return "Experience"
        case .technology: return "Technology"
        case .unutilized: return "Unutilized"
        case .unutilizedHV: return "Unutilized High Value"
        }
    }
}

Call it

print(Filter.allValues)

Prints:

["Salary", "Experience", "Technology", "Unutilized", "Unutilized High Value"]

Answer 13

EDIT: Swift Evolution Proposal SE-0194 Derived Collection of Enum Cases proposes a level headed solution to this problem. We see it in Swift 4.2 and newer. The proposal also points out to some workarounds that are similar to some already mentioned here but it might be interesting to see nevertheless.

I will also keep my original post for completeness' sake.

---

This is yet another approach based on @Peymmankh's answer, adapted to Swift 3.

public protocol EnumCollection: Hashable {}

extension EnumCollection {

public static func allValues() -> [Self] {
    typealias S = Self

    let retVal = AnySequence { () -> AnyIterator<S> in
        var raw = 0
        return AnyIterator {
            let current = withUnsafePointer(to: &raw) {
                 $0.withMemoryRebound(to: S.self, capacity: 1) { $0.pointee }
            }
            guard current.hashValue == raw else { return nil }
            raw += 1
            return current
        }
    }

    return [S](retVal)
}

Answer 14

enum Rank: Int {
    ...
    static let ranks = (Rank.Ace.rawValue ... Rank.King.rawValue).map{Rank(rawValue: $0)! }

}
enum Suit {
    ...
    static let suits = [Spades, Hearts, Diamonds, Clubs]
}

struct Card {
    ...
    static func fullDesk() -> [Card] {
        var desk: [Card] = []
        for suit in Suit.suits {
            for rank in Rank.ranks {
                desk.append(Card(rank: rank,suit: suit))
            }
        }
        return desk
    }
}

How about this?

Answer 15

You can try to enumerate like this

enum Planet: String {
    case Mercury
    case Venus
    case Earth
    case Mars

    static var enumerate: [Planet] {
        var a: [Planet] = []
        switch Planet.Mercury {
            case .Mercury: a.append(.Mercury); fallthrough
            case .Venus: a.append(.Venus); fallthrough
            case .Earth: a.append(.Earth); fallthrough
            case .Mars: a.append(.Mars)
        }
    return a
    }
}

Planet.enumerate // [Mercury, Venus, Earth, Mars]

Answer 16

In Swift 3, when the underlying enum has rawValue, you could implement the Strideable protocol. The advantages are that no arrays of values are created like in some other suggestions and that the standard Swift "for in" loop works, which makes a nice syntax.

// "Int" to get rawValue, and Strideable so we can iterate
enum MyColorEnum: Int, Strideable {
    case Red
    case Green
    case Blue
    case Black

    // required by Strideable
    typealias Stride = Int

    func advanced(by n:Stride) -> MyColorEnum {
        var next = self.rawValue + n
        if next > MyColorEnum.Black.rawValue {
            next = MyColorEnum.Black.rawValue
        }
        return MyColorEnum(rawValue: next)!
    }

    func distance(to other: MyColorEnum) -> Int {
        return other.rawValue - self.rawValue
    }

    // just for printing
    func simpleDescription() -> String {
        switch self {
        case .Red: return "Red"
        case .Green: return "Green"
        case .Blue: return "Blue"
        case .Black: return "Black"
        }
    }
}

// this is how you use it:
for i in MyColorEnum.Red ... MyColorEnum.Black {
    print("ENUM: \(i)")
}

Answer 17

Swift 5 Solution:

enum Suit: String, CaseIterable {
    case spades = "♠"
    case hearts = "♥"
    case diamonds = "♦"
    case clubs = "♣"
}

// access cases like this:

for suitKey in Suit.allCases {
    print(suitKey)
}

Answer 18

This solution strikes the right balance of readability and maintainability.

struct Card {

    // ...

    static func deck() -> Card[] {
        var deck = Card[]()
        for rank in Rank.Ace.toRaw()...Rank.King.toRaw() {
            for suit in [Suit.Spades, .Hearts, .Clubs, .Diamonds] {
                let card = Card(rank: Rank.fromRaw(rank)!, suit: suit)
                deck.append(card)
            }
        }
    return deck
    }
}

let deck = Card.deck()

Answer 19

Sorry, my answer was specific to how I used this post in what I needed to do. For those who stumble upon this question, looking for a way to find a case within an enum, this is the way to do it (new in Swift 2):

Edit: lowercase camelCase is now the standard for Swift 3 enum values

// From apple docs: If the raw-value type is specified as String and you don’t assign values to the cases explicitly, each unassigned case is implicitly assigned a string with the same text as the name of that case.

enum Theme: String
    {
    case white, blue, green, lavender, grey
    }

func loadTheme(theme: String)
    {
    // this checks the string against the raw value of each enum case (note that the check could result in a nil value, since it's an optional, which is why we introduce the if/let block
    if let testTheme = Theme(rawValue: theme)
        {
        // testTheme is guaranteed to have an enum value at this point
        self.someOtherFunction(testTheme)
        }
    }

For those wondering about the enumerating on an enum, the answers given on this page that include a static var/let containing an array of all enum values are correct. The latest Apple example code for tvOS contains this exact same technique.

That being said, they should build a more convenient mechanism into the language (Apple, are you listening?)!

Answer 20

The experiment was: EXPERIMENT

Add a method to Card that creates a full deck of cards, with one card of each combination of rank and suit.

So without modifying or enhancing the given code other than adding the method (and without using stuff that hasn't been taught yet), I came up with this solution:

struct Card {
    var rank: Rank
    var suit: Suit

    func simpleDescription() -> String {
        return "The \(rank.simpleDescription()) of \(suit.simpleDescription())"
    }

    func createDeck() -> [Card] {
        var deck: [Card] = []
        for rank in Rank.Ace.rawValue...Rank.King.rawValue {
            for suit in Suit.Spades.rawValue...Suit.Clubs.rawValue {
                let card = Card(rank: Rank(rawValue: rank)!, suit: Suit(rawValue: suit)!)
                //println(card.simpleDescription())
                deck += [card]
            }
        }
        return deck
    }
}
let threeOfSpades = Card(rank: .Three, suit: .Spades)
let threeOfSpadesDescription = threeOfSpades.simpleDescription()
let deck = threeOfSpades.createDeck()

Answer 21

This seems like a hack but if you use raw values you can do something like this

enum Suit: Int {  
    case Spades = 0, Hearts, Diamonds, Clubs  
 ...  
}  

var suitIndex = 0  
while var suit = Suit.fromRaw(suitIndex++) {  
   ...  
}  

Answer 22

While dealing with Swift 2.0 here is my suggestion:

I have added the raw type to Suit enum

enum Suit: Int {

then:

struct Card {
    var rank: Rank
    var suit: Suit


    func fullDeck()-> [Card] {

        var deck = [Card]()

        for i in Rank.Ace.rawValue...Rank.King.rawValue {

            for j in Suit.Spades.rawValue...Suit.Clubs.rawValue {

                deck.append(Card(rank:Rank(rawValue: i)! , suit: Suit(rawValue: j)!))
            }
        }

        return deck
    }
}

Answer 23

As with @Kametrixom answer here I believe returning an array would be better than returning AnySequence, since you can have access to all of Array's goodies such as count, etc.

Here's the re-write:

public protocol EnumCollection : Hashable {}
extension EnumCollection {
    public static func allValues() -> [Self] {
        typealias S = Self
        let retVal = AnySequence { () -> AnyGenerator<S> in
            var raw = 0
            return AnyGenerator {
                let current : Self = withUnsafePointer(&raw) { UnsafePointer($0).memory }
                guard current.hashValue == raw else { return nil }
                raw += 1
                return current
            }
        }

        return [S](retVal)
    }
}

Answer 24

Another solution:

enum Suit: String {
    case spades = "♠"
    case hearts = "♥"
    case diamonds = "♦"
    case clubs = "♣"

    static var count: Int {
        return 4   
    }

    init(index: Int) {
        switch index {
            case 0: self = .spades
            case 1: self = .hearts
            case 2: self = .diamonds
            default: self = .clubs
        }
    }
}

for i in 0..<Suit.count {
    print(Suit(index: i).rawValue)
}

Answer 25

This is a pretty old post, from Swift 2.0. There are now some better solutions here that use newer features of swift 3.0: Iterating through an Enum in Swift 3.0

And on this question there is a solution that uses a new feature of (the not-yet-released as I write this edit) Swift 4.2: How do I get the count of a Swift enum?

---

There are lots of good solutions in this thread and others however some of them are very complicated. I like to simplify as much as possible. Here is a solution which may or may not work for different needs but I think it works well in most cases:

enum Number: String {
    case One
    case Two
    case Three
    case Four
    case EndIndex

    func nextCase () -> Number
    {
        switch self {
        case .One:
            return .Two
        case .Two:
            return .Three
        case .Three:
            return .Four
        case .Four:
            return .EndIndex

        /* 
        Add all additional cases above
        */
        case .EndIndex:
            return .EndIndex
        }
    }

    static var allValues: [String] {
        var array: [String] = Array()
        var number = Number.One

        while number != Number.EndIndex {
            array.append(number.rawValue)
            number = number.nextCase()
        }
        return array
    }
}

To iterate:

for item in Number.allValues {
    print("number is: \(item)")
}

Answer 26

Enums have toRaw() and fromRaw() methods. So if your raw value is an Int, you can iterate from the first to last enum:

enum Suit: Int {
    case Spades = 1
    case Hearts, Diamonds, Clubs
    func simpleDescription() -> String {
        switch self {
        case .Spades:
            return "spades"
        case .Hearts:
            return "hearts"
        case .Diamonds:
            return "diamonds"
        case .Clubs:
            return "clubs"
        }
    }
}

for i in Suit.Spades.toRaw()...Suit.Clubs.toRaw() {
    if let covertedSuit = Suit.fromRaw(i) {
        let description = covertedSuit.simpleDescription()
    }
}

One gotcha is that you need to test for optional values before running the simpleDescription method, so we set convertedSuit to our value first and then set a constant to convertedSuit.simpleDescription()

Answer 27

Here's my suggested approach. It's not completely satisfactory (I'm very new to Swift and OOP!) but maybe someone can refine it. The idea is to have each enum provide its own range information as .first and .last properties. It adds just two lines of code to each enum: still a bit hard-coded, but at least it's not duplicating the whole set. It does require modifying the Suit enum to be an Int like the Rank enum is, instead of untyped.

Rather than echo the whole solution, here's the code I added to the . enum, somewhere after the case statements (Suit enum is similar):

var first: Int { return Ace.toRaw() }
var last: Int { return King.toRaw() }

and the loop I used to build the deck as an array of String. (The problem definition did not state how the deck was to be structured.)

func createDeck() -> [String] {
    var deck: [String] = []
    var card: String
    for r in Rank.Ace.first...Rank.Ace.last {
        for s in Suit.Hearts.first...Suit.Hearts.last {
            card = Rank.simpleDescription( Rank.fromRaw(r)!)() + " of " + Suit.simpleDescription( Suit.fromRaw(s)!)()
           deck.append( card)
       }
    }
    return deck
}

It's unsatisfactory because the properties are associated to an element rather than to the enum. But it does add clarity to the 'for' loops. I'd like it to say Rank.first instead of Rank.Ace.first. It works (with any element), but it's ugly. Can someone show how to elevate that to the enum level?

And to make it work, I lifted the createDeck method out of the Card struct. I could not figure out how to get a [String] array returned from that struct, and that seems a bad place to put such a method anyway.

Answer 28

I did it using computed property, which returns the array of all values (thanks to this post http://natecook.com/blog/2014/10/loopy-random-enum-ideas/). However, it also uses int raw-values, but I don't need to repeat all members of enumeration in separate property.

UPDATE Xcode 6.1 changed a bit a way how to get enum member using rawValue, so I fixed listing. Also fixed small error with wrong first rawValue.

enum ValidSuits: Int {
    case Clubs = 0, Spades, Hearts, Diamonds
    func description() -> String {
        switch self {
        case .Clubs:
            return "♣︎"
        case .Spades:
            return "♠︎"
        case .Diamonds:
            return "♦︎"
        case .Hearts:
            return "♥︎"
        }
    }

    static var allSuits: [ValidSuits] {
        return Array(
            SequenceOf {
                () -> GeneratorOf<ValidSuits> in
                var i=0
                return GeneratorOf<ValidSuits> {
                    return ValidSuits(rawValue: i++)
                }
            }
        )
    }
}

Answer 29

Here is a method I use to both iterate an enum and provide multiple values types from one enum

enum IterateEnum: Int {
    case Zero
    case One
    case Two
    case Three
    case Four
    case Five
    case Six
    case Seven

    //tuple allows multiple values to be derived from the enum case, and
    //since it is using a switch with no default, if a new case is added,
    //a compiler error will be returned if it doesn't have a value tuple set
    var value: (french: String, spanish: String, japanese: String) {
        switch self {
        case .Zero: return (french: "zéro", spanish: "cero", japanese: "nuru")
        case .One: return (french: "un", spanish: "uno", japanese: "ichi")
        case .Two: return (french: "deux", spanish: "dos", japanese: "ni")
        case .Three: return (french: "trois", spanish: "tres", japanese: "san")
        case .Four: return (french: "quatre", spanish: "cuatro", japanese: "shi")
        case .Five: return (french: "cinq", spanish: "cinco", japanese: "go")
        case .Six: return (french: "six", spanish: "seis", japanese: "roku")
        case .Seven: return (french: "sept", spanish: "siete", japanese: "shichi")
        }
    }

    //Used to iterate enum or otherwise access enum case by index order.
    //Iterate by looping until it returns nil
    static func item(index: Int) -> IterateEnum? {
        return IterateEnum.init(rawValue: index)
    }

    static func numberFromSpanish(number: String) -> IterateEnum? {
        return findItem { $0.value.spanish == number }
    }

    //use block to test value property to retrieve the enum case        
    static func findItem(predicate: ((_: IterateEnum) -> Bool)) -> IterateEnum? {

        var enumIndex: Int = -1
        var enumCase: IterateEnum?

        //Iterate until item returns nil
        repeat {
            enumIndex += 1
            enumCase = IterateEnum.item(index: enumIndex)

            if let eCase = enumCase {

                if predicate(eCase) {
                    return eCase
                }
            }
        } while enumCase != nil
        return nil
    }
}

var enumIndex: Int = -1
var enumCase: IterateEnum?

// Iterate until item returns nil
repeat {
    enumIndex += 1
    enumCase = IterateEnum.item(index: enumIndex)
    if let eCase = enumCase {
        print("The number \(eCase) in french: \(eCase.value.french), spanish: \(eCase.value.spanish), japanese: \(eCase.value.japanese)")
    }
} while enumCase != nil

print("Total of \(enumIndex) cases")

let number = IterateEnum.numberFromSpanish(number: "siete")

print("siete in japanese: \((number?.value.japanese ?? "Unknown"))")

This is the output:

The number Zero in french: zéro, spanish: cero, japanese: nuru
The number One in french: un, spanish: uno, japanese: ichi
The number Two in french: deux, spanish: dos, japanese: ni
The number Three in french: trois, spanish: tres, japanese: san
The number Four in french: quatre, spanish: cuatro, japanese: shi
The number Five in french: cinq, spanish: cinco, japanese: go
The number Six in french: six, spanish: seis, japanese: roku
The number Seven in french: sept, spanish: siete, japanese: shichi

Total of 8 cases

siete in japanese: shichi

---

UPDATE

I recently created a protocol to handle the enumeration. The protocol requires an enum with an Int raw value:

protocol EnumIteration {

    //Used to iterate enum or otherwise access enum case by index order. Iterate by looping until it returns nil

    static func item(index:Int) -> Self?
    static func iterate(item:((index:Int, enumCase:Self)->()), completion:(()->())?) {
    static func findItem(predicate:((enumCase:Self)->Bool)) -> Self?
    static func count() -> Int
}

extension EnumIteration where Self: RawRepresentable, Self.RawValue == Int {

    //Used to iterate enum or otherwise access enum case by index order. Iterate by looping until it returns nil
    static func item(index:Int) -> Self? {
        return Self.init(rawValue: index)
    }

    static func iterate(item:((index:Int, enumCase:Self)->()), completion:(()->())?) {

        var enumIndex:Int = -1
        var enumCase:Self?

        //Iterate until item returns nil
        repeat {
            enumIndex += 1
            enumCase = Self.item(enumIndex)

            if let eCase = enumCase {
                item(index: enumIndex, enumCase: eCase)
            }
        } while enumCase != nil
        completion?()
    }

    static func findItem(predicate:((enumCase:Self)->Bool)) -> Self? {

        var enumIndex:Int = -1
        var enumCase:Self?

        //Iterate until item returns nil
        repeat {
            enumIndex += 1
            enumCase = Self.item(enumIndex)

            if let eCase = enumCase {

                if predicate(enumCase:eCase) {
                    return eCase
                }
            }
        } while enumCase != nil
        return nil
    }

    static func count() -> Int {
        var enumIndex:Int = -1
        var enumCase:Self?

        //Iterate until item returns nil
        repeat {
            enumIndex += 1
            enumCase = Self.item(enumIndex)
        } while enumCase != nil

        //last enumIndex (when enumCase == nil) is equal to the enum count
        return enumIndex
    }
}

Answer 30

enum Rank: Int
{
    case Ace = 0
    case Two, Three, Four, Five, Six, Seve, Eight, Nine, Ten
    case Jack, Queen, King
    case Count
}

enum Suit : Int
{
    case Spades = 0
    case Hearts, Diamonds, Clubs
    case Count
}

struct Card
{
    var rank:Rank
    var suit:Suit
}

class Test
{
    func makeDeck() -> Card[]
    {
        let suitsCount:Int = Suit.Count.toRaw()
        let rankCount:Int = Rank.Count.toRaw()
        let repeatedCard:Card = Card(rank:Rank.Ace, suit:Suit.Spades)
        let deck:Card[] = Card[](count:suitsCount*rankCount, repeatedValue:repeatedCard)

        for i:Int in 0..rankCount
        {
            for j:Int in 0..suitsCount
            {
                deck[i*suitsCount+j] = Card(rank: Rank.fromRaw(i)!, suit: Suit.fromRaw(j)!)
            }
        }
        return deck
    }
}

Based on Rick answer: this is 5 times faster