Regex that will match first case on every line.

Question

I've got the following Regex:

.*?,

And here is some of the data I am working with:

"bagel-mssql-iscsi.private.hostname.ca","3636634643","8.8.8.8"
"cecs-admin.prt.hostname.ca","3636634643","8.8.8.8"
"cecs-admin2.prt.hostname.ca","3636634643","8.8.8.8"

The above data has been censored from the original data.

I want to match:

"bagel-mssql-iscsi.private.hostname.ca",
"cecs-admin.prt.hostname.ca",
"cecs-admin2.prt.hostname.ca",

The problem is that my regex is also matching the numerical value after the hostnames. What can I do so that only the first occurrence of every line is matched. Or an alternative method that would work with this type of data also would work.

Answer 1

Your regex would be,

^".*?",

DEMO

Explanation:

• ^ Asserts that we are at the start.
• " Literal double quotes.
• .*? Reluctant match of any character zero or more times.
• ", Literal " followed by a comma.

Answer 2

You need to anchor to the beginning of the line:

^.*?,

Answer 3

Use ^ anchor which matches only at the beginning of the line:

^.*?,

Answer 4

The Regex Filter below may help:

^\"(\S*?)\",

http://regex101.com/r/dZ3gH8/1