Simplify several boolean conditions java [duplicate]

Question

This question already has answers here:

Test if a string contains any of the strings from an array (13 answers)

Closed 5 years ago.

how would you simplify all these conditions?

String s = "The wold is big"

if(s.contains("is") || s.contains("are") || s.contains("was") || s.contains("were")) 
{ 
    return s;
}

Since I have to check several cases like those, is there a way to simplify all those conditions?

Answer 1

I would write a utility method for that:

public static boolean containsAny(String s, String... words) {
    for (String word : words) {
        if (s.contains(word))
            return true;
    }
    return false;
}

And now:

if (containsAny(s, "is", "are", "was", "were")) {...}

---

Java 8 alternative:

if (Arrays.asList("is", "are", "was", "were").stream().anyMatch(s::contains)) {...}

Answer 2

You can use regex for this using the matches method of the String

sample:

String s = "The wold is big";

    if (s.matches("(.*)(is|are|was|were)(.*)")) {
        System.out.println("lawl");
    }

Answer 3

There is not realy a quicker way to do it. Only if you have a lot of them it would be cleaner to put them in an array and walk over the array.

Also answered here: Test if a string contains any of the strings from an array

Answer 4

You can pass an array of value to check :

public boolean Contains(String[] list, String elem) {
    for (String s: list){
        if(elem.contains(s)) {
            return true;
        }
    }
    return false;
}

String s = "The wold is big"
String[] conditions = {"is","are","was","were"}; 

if(Contains(conditions,s)) 
{ 
    return s;
}