Biztalk Mapper XSLT to strip out string from input

Question

I have an source schema with a node forenames (containing forename + ' ' + middlename), which I need to separate out the middle name in the destination schema so this goes out to OtherNames.

I currently have the following xslt template:

<xsl:template name="StringSplit">
<xsl:param name="valFirstnames" />

<xsl:choose>
  <xsl:when test="contains($valFirstnames, ' ')">
      <xsl:call-template name="StringSplit">
        <xsl:with-param name="valFirstnames" select="substring-after($valFirstnames, ' ')" />
      </xsl:call-template>
  </xsl:when>
  <xsl:otherwise>
     <OtherFirstNames><xsl:value-of select="$valFirstnames" /></OtherFirstNames>
  </xsl:otherwise>
</xsl:choose>
</xsl:template>

Current output for this xslt template is writing out the Middlename twice rather than once:

<OtherFirstName>Middlename</OtherFirstName>
<OtherFirstName>Middlename</OtherFirstName>

Expected:

<OtherFirstName>Middlename</OtherFirstName>

Sample Input

<Data>
  <SubjectName>
    <forenames>first middle</forenames>
  </SubjectName>
  <SubjectPartner>
    <forenames>first middle</forenames>
    <Otherforenames>first middle</Otherforenames>
  </SubjectPartner>
  <etc./>
</Data>

Sample Output

<Data>
  <SubjectName>
    <firstname>first</firstname>
    <OtherFirstName>middle</OtherFirstname>
  </SubjectName>
  <SubjectPartner>
    <firstname>first</firstname>
    <OtherFirstName>middle</OtherFirstName>
    <OtherFirstName>middle</OtherFirstName>
  </SubjectPartner>
  <etc./>
</Data>

I'm looking at correcting the current xslt and updating to incorporate other partner elements that have the same child elements forenames.

Answer 1

Your examples do not make much sense to me. I am guessing you want to do something like:

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="forenames">
    <firstname><xsl:value-of select="substring-before(concat(., ' '), ' ')"/></firstname>
    <xsl:if test="contains(., ' ')">
        <OtherFirstName><xsl:value-of select="substring-after(., ' ')"/></OtherFirstName>
    </xsl:if>
</xsl:template>

</xsl:stylesheet>

Note that this assumes a person has at most two forenames. When applied to the following test input:

<Data>
    <SubjectName>
        <forenames>Alan Benjamin</forenames>
        <surname>Adams</surname>
    </SubjectName>
    <SubjectPartner>
        <forenames>Cecily Diana</forenames>
        <surname>Crown</surname>
    </SubjectPartner>
    <Single>
        <forenames>Eve</forenames>
        <surname>Evans</surname>
    </Single>
    <Triple>
        <forenames>Frank George Herbert</forenames>
        <surname>Forrester</surname>
    </Triple>
</Data>

the result will be:

<?xml version="1.0" encoding="UTF-8"?>
<Data>
   <SubjectName>
      <firstname>Alan</firstname>
      <OtherFirstName>Benjamin</OtherFirstName>
      <surname>Adams</surname>
   </SubjectName>
   <SubjectPartner>
      <firstname>Cecily</firstname>
      <OtherFirstName>Diana</OtherFirstName>
      <surname>Crown</surname>
   </SubjectPartner>
   <Single>
      <firstname>Eve</firstname>
      <surname>Evans</surname>
   </Single>
   <Triple>
      <firstname>Frank</firstname>
      <OtherFirstName>George Herbert</OtherFirstName>
      <surname>Forrester</surname>
   </Triple>
</Data>