# Maximum sum of nodes in Binary tree such that no two are adjacent in C++

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### Question

In this tutorial, we will be discussing a program to find maximum sum of nodes in Binary tree such that no two are adjacent.

For this we will be provided with a binary tree. Our task is to find the subset having maximum sum such that no two nodes in subset are directly connected.

## Example

Live Demo

```#include
using namespace std;
//binary tree node structure
struct node {
int data;
struct node *left, *right;
};
struct node* newNode(int data) {
struct node *temp = new struct node;
temp->data = data;
temp->left = temp->right = NULL;
return temp;
}
int sumOfGrandChildren(node* node);
int getMaxSum(node* node);
int getMaxSumUtil(node* node, map& mp);
int sumOfGrandChildren(node* node, map& mp){
int sum = 0;
if (node->left)
sum += getMaxSumUtil(node->left->left, mp) + getMaxSumUtil(node->left->right, mp);
if (node->right)
sum += getMaxSumUtil(node->right->left, mp) + getMaxSumUtil(node->right->right, mp);
return sum;
}
//returning maximum sum
int getMaxSumUtil(node* node, map& mp) {
if (node == NULL)
return 0;
if (mp.find(node) != mp.end())
return mp[node];
int incl = node->data + sumOfGrandChildren(node, mp);
int excl = getMaxSumUtil(node->left, mp) + getMaxSumUtil(node->right, mp);
mp[node] = max(incl, excl);
return mp[node];
}
int getMaxSum(node* node) {
if (node == NULL)
return 0;
map mp;
return getMaxSumUtil(node, mp);
}
int main() {
node* root = newNode(1);
root->left = newNode(2);
root->right = newNode(3);
root->right->left = newNode(4);
root->right->right = newNode(5);
root->left->left = newNode(1);
cout << getMaxSum(root) << endl;
return 0;
}```

## Output

`11`
Published on 09-Sep-2020 13:10:07