Get the integral part of a BigFraction, as a BigInteger
-
13-09-2020 - |
Question
What is an easy way to get the integral part of a BigFraction
as a BigInteger
?
Basically I want the same result that the intValue
and longValue
methods return but with arbitrary precision.
I also want to avoid rounding so indirect conversion via a BigDecimal
is not suitable.
Solution
myBigFraction.getNumerator().divide( myBigFraction.getDemoninator() );
?
OTHER TIPS
You could try something like this
BigFraction fraction = ...
BigInteger num = fraction.getNumerator();
BigInteger den = fraction.getDenominator();
BigInteger[] divideAndReminder = num.divideAndRemainder(den);
Then finally
BigInteger integralPart = divideAndReminder[0];
This should do the trick.
bigInteger = bigFraction.genNumerator().divide(bigFraction.getDenominator());
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