syntax error in Regular expression to match link url

Question

I have the following method in some nemerle code:

private static getLinks(text : string) : array[string] {
        def linkrx = Regex(@"<a\shref=['|\"](.*?)['|\"].*?>");
        def m = linkrx.Matches(text);
        mutable txmatches : array[string];
        for (mutable i = 0; i < m.Count; ++i) {
            txmatches[i] = m[i].Value;
        }
        txmatches
    }

the problem is that the compiler for some reason is trying to parse the brackets inside the regex statement and its causing the program to not compile. If i remove the @, (which i was told to put there) i get an invalid escape character error on the "\s"

Heres the compiler output:

NCrawler.n:23:21:23:22: ←[01;31merror←[0m: when parsing this `(' brace group
NCrawler.n:23:38:23:39: ←[01;31merror←[0m: unexpected closing bracket `]'
NCrawler.n:22:57:22:58: ←[01;31merror←[0m: when parsing this `{' brace group
NCrawler.n:23:38:23:39: ←[01;31merror←[0m: unexpected closing bracket `]'
NCrawler.n:8:1:8:2: ←[01;31merror←[0m: when parsing this `{' brace group
NCrawler.n:23:38:23:39: ←[01;31merror←[0m: unexpected closing bracket `]'
NCrawler.n:23:38:23:39: ←[01;31merror←[0m: unexpected closing bracket `]'

(line 23 is the line with the regex code on it)

What should I do?

Answer 1

I don't know Nemerle, but it seems like using @ disables all escapes, including the escape for the ".

Try one of these:

def linkrx = Regex("<a\\shref=['\"](.*?)['\"].*?>");

def linkrx = Regex(@"<a\shref=['""](.*?)['""].*?>");

def linkrx = Regex(@"<a\shref=['\x22](.*?)['\x22].*?>");

Answer 2

I'm not Nemerle programmer but i know that yous shoud ALWAYS use XML parser for XML based data and not regexps.

I guess someone has created DOM or XPath library for Nemerle so you can access either

//a[@href] via XPath or something like a.href.value via DOM.

That current regexp doesn't like for example

<a class="foo" href="something">bar</a>

I didn't test this but it should be more like it

/<a\s.+?href=['|\"]([^'\">]+)['|\"].+?>/i

Answer 3

The problem is with the quotation marks, not the brackets. In Nemerle, as in C#, you escape a quotation mark with another quotation mark, not a backslash.

@"<a\shref=['""](.*?)['""].*?>"

EDIT: Note as well that you don't need the pipe inside the square brackets; the contents are treated as a set of characters (or ranges of characters), with the OR being implied.