What is the third boolean state in java?
Question
While I know that by definition a boolean consists of only two states, true or false. I was wondering what value does a boolean have before it is initialized with one of these states.
Solution
Edit: By popular demand:
unless you're using the wrapped Boolean, which defaults to null. – sudhir.j
OTHER TIPS
If it is a local variable, it is a compiler error to reference it before it was initialized. If it is a field, it is initialized to false.
public class NewMain {
boolean foo;
Boolean bar;
public static void main(String[] args) {
NewMain obj = new NewMain();
obj.whatBoolean();
}
public void whatBoolean() {
System.out.println(foo);
System.out.println(bar);
}
}
outputs
false
null
I know this was more philosophical of a question, but thanks to autoboxing you can use Java as a almost truly OO language (I hate having primitive types... now only if it would work in reverse too). It does, however, change the behavior when you use an object (for the better IMO).
There is no third state. As @Yishai said, if you don't assign a value, boolean fields default to false. Local variables must be assigned before use:
Accessing an uninitialized local variable will result in a compile-time error
See the doc.
In JAVA boolean types default to False.
FYI, boolean defaults to false, primitive numbers default to 0, 0L, 0f or 0d as appropriate, char defaults to '\0', Object references (such as Boolean) default to null.
This also applies to the contents of arrays. (A common gotcha is that an array of Objects is initially full of null values)
It is false
If you had something like
boolean isTrue;
System.out.println(isTrue);
You should get a compile time error because the boolean wasn't initialized. By default when you try to initialize this it will be set to false;