Auto GET to argument of view

Question

some_view?param1=10&param2=20

def some_view(request, param1, param2):

Is such possible in Django?

Answer 1

You could always write a decorator. Eg. something like (untested):

def map_params(func):
    def decorated(request):
        return func(request, **request.GET)
    return decorated

@map_params
def some_view(request, param1, param2):
    ...

Answer 2

I'm not sure it's possible to get it to pass them as arguments to the view function, but why can't you access the GET variables from request.GET? Given that URL, Django would have request.GET['param1'] be 10 and request.GET['param2'] be 20. Otherwise, you'd have to come up with some kind of weird regular expression to try and do what you want.

Answer 3

I agree with Paolo... the stuff after the '?' are GET parameters and should probably be treated as such. That said, if you really want to keep the definition of some_view() as you've stated in the question, you could do something like:

from django.http import Http404
def some_view_proxy(request):
     if 'param1' in request.GET and 'param2' in request.GET:
         return some_view(request, request.GET['param1'],
                          request.GET['param2'])
     raise Http404

Or you could just define some_view() like this and use the GET params. Just curious, why do you want that?

Answer 4

Instead of fighting Django, why not just request some_view/10/20 and then set up urls.py to extract the arguments?