IndexError: list index out of range and python

Question

I'm telling my program to print out line 53 of an output. Is this error telling me that there aren't that many lines and therefore can not print it out?

Answer 1

If you have a list with 53 items, the last one is thelist[52] because indexing start at 0.

Answer 2

Yes,

You are trying to access an element of the list that does not exist.

MyList = ["item1", "item2"]
print MyList[0] # Will work
print MyList[1] # Will Work
print MyList[2] # Will crash.

Have you got an off-by-one error?

Answer 3

Yes. The sequence doesn't have the 54th item.

Answer 4

That's right. 'list index out of range' most likely means you are referring to n-th element of the list, while the length of the list is smaller than n.

Answer 5

Always keep in mind when you want to overcome this error, the default value of indexing and range starts from 0, so if total items is 100 then l[99] and range(99) will give you access up to the last element.

whenever you get this type of error please cross check with items that comes between/middle in range, and insure that their index is not last if you get output then you have made perfect error that mentioned above.

Answer 6

The way Python indexing works is that it starts at 0, so the first number of your list would be [0]. You would have to print[52], as the starting index is 0 and therefore line 53 is [52].

Subtract 1 from the value and you should be fine. :)

Answer 7

If you read a list from text file, you may get the last empty line as a list element. You can get rid of it like this:

list.pop()
for i in list:
   i[12]=....