SPARQL Query problem -> wrong answer

Question

I want to select a triple using SPARQL. To do it, i'm using following query:

SELECT count (*)
WHERE {?s ?p ?o}
FILTER (?s=http://kjkhlsa.net && ?p=http://lkasdjlkjas.com && ?o=Test)

As answer i get fully wrong triple :( subject ist not equal to "http://kjkhlsa.net", predicate is not equal to "http://lkasdjlkjas.com" and object ist also not equal to "Test". Can someone explain me, what I'm doing wrong :(

edit1: I have put the query into php file:

    $inst_query = 'SELECT * { <http://kjkhlsa.net> <http://lkasdjlkjas.com> "Test"}';
    echo $inst_query;

The answer from the echo was "SELECT * { "Test"}". Then i tried it with WHERE:

    $inst_query = 'SELECT * WHERE { <http://kjkhlsa.net> <http://lkasdjlkjas.com> "Test"}';
    echo $inst_query;

Here was the answer "SELECT * WHERE { "Test"}"...so, i'm missing the URIs, but this seems for me as php issue and not sparql problem.

edit2: I've put the query into SPARQL Query editor and i get the response "no result"....but I'm sure, that i have this triple.

Answer 1

In its current form the question is not very clear (see my comment above).

Since you are essentially trying to get triples matching a pattern, it is more efficient to use a graph pattern instead of FILTER. Many SPARQL implementations first match candidate triples by graph patterns and only then apply the FILTER expression. In essence, with a ?s ?p ?o graph pattern, you're doing a linear scan over all your triples.

So, here's something that should work, using graph patterns instead of FILTER.

SELECT * { <http://kjkhlsa.net> <http://lkasdjlkjas.com> "Test" }

Notes: I didn't include COUNT(*) which is not standard SPARQL. <> around URIs. "" around literal.

Answer 2

Try to use this :

SELECT count (*) as ?count
WHERE {
    ?s ?p ?o
FILTER (?s=<http://kjkhlsa.net> && ?p=<http://lkasdjlkjas.com> && ?o=Test)
}

Answer 3

The following query uses the count function to count the number of distinct URI(s) returned to the ?s variable.

 SELECT ?s (COUNT (DISTINCT ?s) as ?count)
    WHERE {?s ?p ?o}
    FILTER (?o="Test")