mysql create database and user script

Question

Question Rewritten:

HOMEDIR="ftpuser"
REMOTEIP="1.1.1.1"
MYSQLPASS="password"

Q1="DROP USER "$HOMEDIR"_shop;"
Q2="DROP DATABASE "$HOMEDIR"_shop;"
Q3="CREATE DATABASE IF NOT EXISTS "$HOMEDIR"_shop;"
Q4="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'@'localhost' IDENTIFIED BY '$MYSQLPASS';"
Q5="GRANT ALL ON "$HOMEDIR"_shop TO '"$HOMEDIR"_shop'@'anotherip' IDENTIFIED BY '$MYSQLPASS';"
# Need to grant permissions from another server as well
Q6="FLUSH PRIVILEGES;"
SQL="${Q1}${Q2}${Q3}${Q4}${Q5}${Q6}"

echo $SQL
echo " "
ssh -p 8899 root@$REMOTEIP "mysql -u root -p "$SQL""

I then run:

/root/testing/migratesite.sh

And get:

bash: DROP: command not found
bash: CREATE: command not found
bash: GRANT: command not found
bash: GRANT: command not found
bash: FLUSH: command not found

What am I missing?

Answer 1

You are missing quotes and a proper mysql client command line:

ssh -p 8899 root@$REMOTEIP "mysql -u root -p -e \"$SQL\""

You need to escape the quotes around the $SQL variable so they get passed to the remote shell, else they get interpreted by the local shell (that's why you get DROP: command not found, the semi colon is interpreted by the shell.) Also, to have the mysql client to execute a command you have to pass the -e command line option.

Answer 2

Did you try this:

ssh -p 8899 root@$REMOTEIP "echo \"$SQL\" | mysql -u root --password=$SQL_PASS"