What's the “condition” in C interview test?

Question

Would it be possible to print Hello twice using single condition?

if  "condition"
  printf ("Hello");
else
  printf("World");

Answer 1

if ( printf("Hello") == 0 )
    printf ("Hello");
else
    printf ("World");

:-)

Answer 2

"condition" === (printf("Hello"), 0)

Really lame:

int main() {
    if  (printf("Hello"), 0)
        printf ("Hello");
    else
        printf("World");
}

I prefer the use of the comma operator because you don't have to look up the return value of printf in order to know what the conditional does. This increases readability and maintainability. :-)

Answer 3

This sounds to me like some interview puzzle. I hope this is close to what you want.

#include <stdio.h>

int main()
{
 static int i = 0 ;
 if( i++==0 ? main(): 1)
  printf("Hello,");
 else
  printf("World\n");

 return 0 ;
}

prints Hello, World

Answer 4

Buckle your seatbelts:

#include <stdio.h>
#include <setjmp.h>

int main()
{
    jmp_buf env;

    if (!setjmp(env))
    {
        printf("if executed\n");
        longjmp(env, 1);
    }
    else
    {
        printf("else executed\n");
    }

    return 0;
}

Prints:

if executed
else executed

Is this what you mean? I doubt it, but at least it's possible. Using fork you can do it also, but the branches will run in different processes.

Answer 5

If it is on Unix:

if  (fork())
    printf ("Hello");
else
    printf("World");

Ofcoures that doesn't guarantee the order 0f the prints

Answer 6

#define CONDITION (0) if (0) {} else

or some such.

If you see such a question on an interview, run away as fast as you can! The team that asks such questions is bound to be unhealthy.

Edit - I forgot to clarify - this relies on "else" being matched with closest open "if", and on the fact that it's written as "if CONDITION" rather than if (CONDITION) - parenthesis would make the puzzle unsolvable.

Answer 7

if ( printf("Hello")==0)

see [http://www.coders2020.com/what-does-printf-return]

(matt corrected my =, thanks, C is far away)

Answer 8

The if statement executes one or the other of the controlled statements (both printf in your example). No matter what you use for condition, that snippet will either print "Hello", or "World", but never both.

Edit: Okay, so it's a trick question and you can put whatever you like in the condition (including a call to an entire other function that does anything you want). But that's hardly interesting. I can't believe I got downmodded for giving a correct answer.

Answer 9

Comment the "else" ;)

if(foo)
{
    bar();
}
//else
{
    baz();
}

Answer 10

Without knowing the return value of printf off the top of your head:

if (printf("Hello") && 0)
    printf("Hello");
else
    printf("World");

Answer 11

The basic answer is that in the ordinary course of events you neither want to execute both the statements in the 'if' block and the 'else' block in a single pass through the code (why bother with the condition if you do) nor can you execute both sets of statements without jumping through grotesque hoops.

Some grotesque hoops - evil code!

    if (condition == true)
    {
         ...stuff...
         goto Else;
    }
    else
    {
Else:
        ...more stuff...
    }

Of course, it is a plain abuse of (any) language because it is equivalent to:

    if (condition == true)
    {
         ...stuff...
    }
    ...more stuff...

However, it might achieve what the question is asking. If you have to execute both blocks whether the condition is true or false, then things get a bit trickier.

    done_then = false;
    if (condition == true)
    {
Then:
         ...stuff...
         done_then = true;
         goto Else;
    }
    else
    {
Else:
        ...more stuff...
        if (!done_then) goto Then;
    }

Answer 12

int main()
{
    runIfElse(true);
    runIfElse(false);

    return 0;
}

void runIfElse(bool p)
{
    if(p)
    {
     // do if
    }
    else
    {
     // do else
    }
}

Answer 13

if  (true) printf ("Hello"); if (false)
    printf ("Hello");
else
    printf("World");

Answer 14

No love for exit?

if(printf("HelloWorld"), exit(0), "ByeBye") 
    printf ("Hello");
else
    printf ("World");

Answer 15

So... you want to execute the code inside the if block... and the code inside of the else block... of the same if/else statement? Then... you should get rid of the else and stick taht code in the if.

if something
  do_this
  do_that
end

The else statement is designed to execute only if the if statement is not executed and vice-versa, that is the whole point. This is an odd question...

Answer 16

This could work:

if (printf("Hello") - strlen("Hello"))
    printf("Hello")
else
    printf("World")

This snippet emphasizes the return value of printf: The number of characters printed.

Answer 17

Just put the code before or after the if..else block.

Alternatively, if you have an "if, else if, else" block where you want to execute code in some (but not all) branches, just put it in a separate function and call that function within each block.

Answer 18

Solution 1:

int main(int argc, char* argv[])
{   
    if( argc == 2 || main( 2, NULL ) )
    {
        printf("Hello ");   
    }
    else
    {
        printf("World\n");
    }
    return 0;
}

Solution 2 (Only for Unix and Linux):

int main(int argc, char* argv[])
{   
    if( !fork() )
    {
        printf("Hello ");   
    }
    else
    {
        printf("World\n");
    }
    return 0;
}

Answer 19

 #include<stdio.h>
  int main()
{
 if(! printf("Hello"))
     printf ("Hello");
else
    printf ("World");
 return 0;
}

Because Printf returns the number of character it has printed successfully.

Answer 20

if(printf("Hello") == 1)
    printf("Hello")
else
    printf("World")

Answer 21

if (printf("Hello") < 1)
    printf("Hello");
else
    printf("World");

Answer 22

Greg wrote:

No matter what you use for condition, that snippet will either print "Hello", or "World", but never both.

Well, this isn't true, but why you would want it to print both, I can't find a use case for. It's defeating the point of having an if statement. The likely "real" solution is to not use an if at all. Silly interview questions... :)

Answer 23

Very interesting guys, thanks for the answers. I never would have thought about putting the print statement inside the if condition.

Here's the Java equivalent:

    if ( System.out.printf("Hello").equals("") )
        System.out.printf("Hello");
    else
        System.out.printf("World");

Answer 24

Dont use an if else block then.

EDIT to Comment.

It might then mean that the code be in both blocks, or before/after the block if it is required to run in both cases.

Answer 25

use a goto, one of the single most underused keywords of our day

Answer 26

Cheeting with an empty else statement:

if (condition)
    // do if stuff
else;
    // do else stuff

If you don't like the fact that else; is actually an empty else statement try this:

for (int ii=0; ii<2; ii++)
{
    if (condition && !ii)
        // do if stuff
    else
    {
        // do else stuff
        break;
    }
}

Answer 27

Two possible Solutions without using printf statements :-

First :-

#include <stdio.h>

int
main(void)
{
  if (!stdin || (stdin = 0, main()))
    printf("hello");
  else
    printf("world");
  return 0;
}

Second

#include<stdio.h>
void main()
{
if (1
#define else if (1) 
)
{ 
  printf("hello"); 
} 
else
 { 
    printf("world"); 
}
}

Reference :- Link1 , Link2

Answer 28

if (printf("hello") & 0)
{
printf("hello");
}
else
{
printf("world");

No need to bother about the return value of printf.

Answer 29

Abuse of preprocessing - with cleanup at least.

#define else 
if(1)
{
   printf("hello");
}
else
{
   printf("world");
}
#undef else

Answer 30

The condition to this question is:

 if(printf("hello")? 0 : 1) {   }