What is the difference between the | and || or operators?

Question

I have always used || (two pipes) in OR expressions, both in C# and PHP. Occasionally I see a single pipe used: |. What is the difference between those two usages? Are there any caveats when using one over the other or are they interchangeable?

Answer 1

Just like the & and && operator, the double Operator is a "short-circuit" operator.

For example:

if(condition1 || condition2 || condition3)

If condition1 is true, condition 2 and 3 will NOT be checked.

if(condition1 | condition2 | condition3)

This will check conditions 2 and 3, even if 1 is already true. As your conditions can be quite expensive functions, you can get a good performance boost by using them.

There is one big caveat, NullReferences or similar problems. For example:

if(class != null && class.someVar < 20)

If class is null, the if-statement will stop after class != null is false. If you only use &, it will try to check class.someVar and you get a nice NullReferenceException. With the Or-Operator that may not be that much of a trap as it's unlikely that you trigger something bad, but it's something to keep in mind.

No one ever uses the single & or | operators though, unless you have a design where each condition is a function that HAS to be executed. Sounds like a design smell, but sometimes (rarely) it's a clean way to do stuff. The & operator does "run these 3 functions, and if one of them returns false, execute the else block", while the | does "only run the else block if none return false" - can be useful, but as said, often it's a design smell.

There is a Second use of the | and & operator though: Bitwise Operations.

Answer 2

|| is the logical OR operator. It sounds like you basically know what that is. It's used in conditional statements such as if, while, etc.

condition1 || condition2

Evaluates to true if either condition1 OR condition2 is true.

| is the bitwise OR operator. It's used to operate on two numbers. You look at each bit of each number individually and, if one of the bits is 1 in at least one of the numbers, then the resulting bit will be 1 also. Here are a few examples:

A = 01010101
B = 10101010
A | B = 11111111

A = 00000001
B = 00010000
A | B = 00010001

A = 10001011
B = 00101100

A | B = 10101111

Hopefully that makes sense.

So to answer the last two questions, I wouldn't say there are any caveats besides "know the difference between the two operators." They're not interchangeable because they do two completely different things.

Answer 3

One is a "bitwise or".

10011b | 01000b => 11011b

The other is a logic or.

true or false => true

Answer 4

Good question. These two operators work the same in PHP and C#.

| is a bitwise OR. It will compare two values by their bits. E.g. 1101 | 0010 = 1111. This is extremely useful when using bit options. E.g. Read = 01 (0X01) Write = 10 (0X02) Read-Write = 11 (0X03). One useful example would be opening files. A simple example would be:

File.Open(FileAccess.Read | FileAccess.Write);  //Gives read/write access to the file

|| is a logical OR. This is the way most people think of OR and compares two values based on their truth. E.g. I am going to the store or I will go to the mall. This is the one used most often in code. E.g.

if(Name == "Admin" || Name == "Developer) { //allow access } //checks if name equals Admin OR Name equals Developer

PHP Resource: http://us3.php.net/language.operators.bitwise

C# Resources: http://msdn.microsoft.com/en-us/library/kxszd0kx(VS.71).aspx

http://msdn.microsoft.com/en-us/library/6373h346(VS.71).aspx

Answer 5

Simple example in java

public class Driver {

  static int x;
  static int y;

public static void main(String[] args) 
throws Exception {

System.out.println("using double pipe");
    if(setX() || setY())
        {System.out.println("x = "+x);
        System.out.println("y = "+y);
        }



System.out.println("using single pipe");
if(setX() | setY())
    {System.out.println("x = "+x);
    System.out.println("y = "+y);
    }

}

 static boolean setX(){
      x=5;
     return true;
  }
 static boolean setY(){
      y=5;
      return true;
  }
}

output :

using double pipe
x = 5
y = 0
using single pipe
x = 5
y = 5

Answer 6

& - (Condition 1 & Condition 2): checks both cases even if first one is false

&& - (Condition 1 && Condition 2): dosen't bother to check second case if case one is false

&& - operator will make your code run faster, professionally & is rarely used

| - (Condition 1 | Condition 2): checks both cases even if case 1 is true

|| - (Condition 1 || Condition 2): dosen't bother to check second case if first one is true

|| - operator will make your code run faster, professionally | is rarely used

Answer 7

The single pipe, |, is one of the bitwise operators.

From Wikipedia:

In the C programming language family, the bitwise OR operator is "|" (pipe). Again, this operator must not be confused with its Boolean "logical or" counterpart, which treats its operands as Boolean values, and is written "||" (two pipes).

Answer 8

By their mathematical definition, OR and AND are binary operators; they verify the LHS and RHS conditions regardless, similarly to | and &.

|| and && alter the properties of the OR and AND operators by stopping them when the LHS condition isn't fulfilled.

Answer 9

The | operator performs a bitwise OR of its two operands (meaning both sides must evaluate to false for it to return false) while the || operator will only evaluate the second operator if it needs to.

http://msdn.microsoft.com/en-us/library/kxszd0kx(VS.71).aspx

http://msdn.microsoft.com/en-us/library/6373h346(VS.71).aspx

Answer 10

The singe pipe "|" is the "bitwise" or and should only be used when you know what you're doing. The double pipe "||" is a logical or, and can be used in logical statements, like "x == 0 || x == 1".

Here's an example of what the bitwise or does: if a=0101 and b=0011, then a|b=0111. If you're dealing with a logic system that treats any non-zero as true, then the bitwise or will act in the same way as the logical or, but it's counterpart (bitwise and, "&") will NOT. Also the bitwise or does not perform short circuit evaluation.

Answer 11

A single pipe (|) is the bitwise OR operator.

Two pipes (||) is the logical OR operator.

They are not interchangeable.

Answer 12

|| (two pipes) is usually a logical or while | (one pipe) is a binary or. Off the top of my head, I can't think of any time the difference would be a big gotcha (other than when you're assigning the result to something else). However I sure someone else will have a situation where it matters.

Edit: Wow, six other answers in the time it took me to write this.

Answer 13

Bitwise (|) vs. logical(||)! Think of logical as the Comparable objects in Java, comparing some distinguishable "parts" while the bitwise operator looks at these objects and instead of seeing if they are visually twins (like logical does), does a DNA sample and looks at the 0's and 1's instead.