How to output each file and folder in directory hierarchy

Question

I'm looking for a way to all files and folders and files in those folders.

As an example.

if I have

- Root
+ file1
+ file2
-- Directory
-+ file1
-+ file2
---Directory
--+ file1
--+ file2

I would like to be able to output each one of those files in the program so it would be like:

root/file1
root/file2
root/Directory/file1
root/Directory/file2
root/Directory/Directory/file1
root/Directory/Directory/file2

As matching to the folder hierarchy.

Is there anyway to do this?

Thanks

Answer 1

The following example does exactly what you want:-

http://www.dotnetperls.com/recursively-find-files

Answer 2

use DirectoryInfo class,FileInfo classes inside your System.IO to get these details.

 public void PrintAllFiles()
    {
        DirectoryInfo obj = new DirectoryInfo("E:\\");
        foreach (var k in obj.GetFiles())
        {
            Console.WriteLine(k.FullName);
        }
    }

Answer 3

Using Linq for some of the lifting

var di=new DirectoryInfo(folderPath);
var files=di.GetFiles("*",SearchOption.AllDirectories).Select(f=>f.FullName.Substring(di.FullName.Length+1));

miss out the substring to get the full path. Or if you just want the folder name of the root object (eg if you did c:\users\bob\fish as the directory and you just wanted fish\foldername you would do the following..

var di=new DirectoryInfo(folderPath);
var basePath=Path.GetDirectoryName(folderPath);
var files=di.GetFiles("*",SearchOptions.AllDirectorys).Select(f=>f.FullName.Substring(basePth.Length+1));

if you tag an extra .Select(f=>f.Replate(@"\","/")) on the end of the statement you can use / as the path seperator instead of \

Answer 4

you could use System.IO.Directory.GetFiles(..,..,System.IO.SearchOption.AllDirectories) which returns an array of files and full path names and then print that array. if you need sorting you could recursively loop through directories and use System.IO.Directory.GetFiles(..,..,System.IO.SearchOption.TopDirectoryOnly) on each directory instead.