SQL statement with LIKE

Question

I would like to select all records that have an underscore character in their 11th character, so i try this:

SELECT * FROM "BOM_SUB_LEVEL" where TOP_CODE like '%%%%%%%%%%_%%%'

but this doesnt work as expected, can someone help?

Answer 1

Just use the "SUBSTRING" function :

SELECT * FROM "BOM_SUB_LEVEL" where SUBSTRING(TOP_CODE, 11, 1) = "_"

Marc

Answer 2

For a single character wildcard use _. For multiple characters wildcards, use %. To escape a "real" appearance of _, use \_ (thanks Bill!).

Try the following code:

SELECT * FROM "BOM_SUB_LEVEL" where TOP_CODE like '___________\_%'

To further elaborate following Dav's comment, note that '%%%' is exactly the same as '%', since by definition '%' covers multiple characters.

Answer 3

pervasive uses _ to match any single character and \_ to actually match an underscore.

so the select would be:

SELECT * FROM "BOM_SUB_LEVEL" where TOP_CODE like '___________\_%' 

Answer 4

LIKE % can mean any number of characters, use LIKE _ to mean just one. Since you're looking for an underscore, you need to escape it with !.

SELECT * FROM BOM_SUB_LEVEL WHERE TOP_CODE LIKE '__________!_%'

Answer 5

The % is not a per character wildcard, its a beginning and end of string wild card.

i.e. if I want to find all rows that have "car" in them, I would do this:

Select * from myTable where myCol LIKE '%car%'

If I wanted just the rows that STARTED with car:

Select * from myTable where myCol LIKE 'car%'

and ended with car:

Select * from myTable where myCol LIKE '%car'

Answer 6

% is a wildcard and can replace an character, or combination of characters. Use ? instead which replaces a single character.

Answer 7

You can try something like: (play with the numbers, I don't have pervasive to test with)

SELECT * 
  FROM BOM_SUB_LEVEL 
 where SUBSTRING(TOP_CODE, 11,1) = '-'