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Solution

Well, first the binomial can be taken outside the sum and the sum can be performed in closed form:

the sum

Anyway, the entire expression you gave is entered into maxima as

u(a, m, n) := (-h)^(n-a) * sum((-1)^j * binomial(a-n,n) * (1+h)^j, j, 0, m-n);
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