Check if User Inputs a Letter or Number in C

Question

Is there an easy way to call a C script to see if the user inputs a letter from the English alphabet? I'm thinking something like this:

if (variable == a - z) {printf("You entered a letter! You must enter a number!");} else (//do something}

I want to check to make sure the user does not enter a letter, but enters a number instead. Wondering if there is an easy way to pull every letter without manually typing in each letter of the alphabet :)

Answer 1

#include <ctype.h>
if (isalpha(variable)) { ... }

Answer 2

It's best to test for decimal numeric digits themselves instead of letters. isdigit.

#include <ctype.h>

if(isdigit(variable))
{
  //valid input
}
else
{
  //invalid input
}

Answer 3

isalpha() will test one character at a time. If the user input a number like 23A4, then you want to test every letter. You can use this:

bool isNumber(char *input) {
    for (i = 0; input[i] != '\0'; i++)
        if (isalpha(input[i]))
            return false;
    return true;
}

// accept and check
scanf("%s", input);  // where input is a pointer to a char with memory allocated
if (isNumber(input)) {
    number = atoi(input);
    // rest of the code
}

I agree that atoi() is not thread safe and a deprecated function. You can write another simple function in place of that.

Answer 4

Aside from the isalpha function, you can do it like this:

char vrbl;

if ((vrbl >= 'a' && vrbl <= 'z') || (vrbl >= 'A' && vrbl <= 'Z')) 
{
    printf("You entered a letter! You must enter a number!");
}

Answer 5

The strto*() library functions come in handy here:

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#define SIZE ...

int main(void)
{
  char buffer[SIZE];
  printf("Gimme an integer value: ");
  fflush(stdout);
  if (fgets(buffer, sizeof buffer, stdin))
  {
    long value;
    char *check;
    /**
     * strtol() scans the string and converts it to the equivalent 
     * integer value.  check will point to the first character
     * in the buffer that isn't part of a valid integer constant;
     * e.g., if you type in "12W", check will point to 'W'.  
     *
     * If check points to something other than whitespace or a 0
     * terminator, then the input string is not a valid integer. 
     */
    value = strtol(buffer, &check, 0);
    if (!isspace(*check) && *check != 0)
    {
      printf("%s is not a valid integer\n", buffer);
    }
  }
  return 0;
}

Answer 6

You can also do it with few simple conditions to check whether a character is alphabet or not

if((ch>='a' && ch<='z') || (ch>='A' && ch<='Z'))
{
    printf("Alphabet");
}

Or you can also use ASCII values

if((ch>=97 && ch<=122) || (ch>=65 && ch<=90))
{
    printf("Alphabet");
}

Answer 7

int strOnlyNumbers(char *str)
{
 char current_character;
 /* While current_character isn't null */
 while(current_character = *str)
 {
  if(
     (current_character < '0')
    ||
     (current_character > '9')
    )
  {
   return 0;
  }
  else
  {
   ++str;
  }
 }
 return 1;
}