jqGrid Basic Column Chooser

Question

jqGrid has a column chooser functionality as like described here:

http://www.trirand.com/jqgridwiki/doku.php?id=wiki:jquery_ui_methods

and a demonstration from @Oleg:

http://www.ok-soft-gmbh.com/jqGrid/SimpleLocalGridWithColumnChooser.htm

However its too complex for my needs. Is there any simple way as like FlexGrid's show-hide columns choosing functionality:

http://flexigrid.info/

You can check Example 1. Columns can be shown and hide by clicking columns. I don't want to same thing but it would be great just clicking somewhere at or near columns and choosing just columns to show or hide.

Any ideas?

PS: I want a basic show-hide column field not a complex screen that opens and people selects many options on them. It should be build on table as like Flexigirid. users click checkboxes and thats all.

Answer 1

Sorry, but you can't have the same look in one software product like you know in another one.

Do you can configure flexigrid so that it looks like jqGrid? Do you can that iPhone looks like Windows Phone or Mac OS X looks like Windows? Every software product has its own design and the set of features.

The columnCooser are based on the multiselect widget and allows you to show or hide any columns or reorder columns with respect of drag & drop. flexigrid has another implementation of the features.

If you want to use some free open soure product you should understand the features and the possibilities which provide the product and just use there.