Question

PHP's extract() function can take on one of several extract_types. But what's the difference between extr_prefix_same and extr_prefix_if_exists? The manual makes it sound like, in either case, new variables will be prefixed if the variable name already exists.

Thanks!

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Solution

When using EXTR_PREFIX_IF_EXISTS, if the variable doesn't already exist then the prefixed version won't be created either. In this example:

function test() {
    $a = 12345;

    extract(array('a' => 1, 'b' => 2, 'c' => 3), EXTR_PREFIX_IF_EXISTS, 'my_');

    var_export(get_defined_vars());
}
test();

$my_b and $my_c aren't created because $b and $c don't exist.

OTHER TIPS

EXTR_PREFIX_SAME will extract all variables, and only prefix ones that exist in the current scope.

EXTR_PREFIX_IF_EXISTS will only extract variables that exist in the current scope, and prefix them with the desired prefix.

So, for example:

$foo = 'foo';
$bar = 'bar';

extract(array('foo' => 'moo', 'bar' => 'mar', 'baz' => 'maz'), EXTR_PREFIX_IF_EXISTS, 'prefix');

isset($prefix_foo); // true
isset($prefix_baz); // false
isset($baz); // false

While....

$foo = 'foo';
$bar = 'bar';

extract(array('foo' => 'moo', 'bar' => 'mar', 'baz' => 'maz'), EXTR_PREFIX_SAME, 'prefix');

isset($prefix_foo); // true
isset($prefix_baz); // false
isset($baz); // true

Based on the manual definitions, EXTR_PREFIX_SAME will create variables based on the key name, and if a variable in the local space already exists, a prefix will be added to the variable name.

By contrast, EXTR_PREFIX_IF_EXISTS would appear to inherit the behavior of EXTR_IF_EXISTS (only overwrite if the variables already exist), but instead of overwriting the local variables, a prefixed version will be created.

Consider the following

$array = Array();
$array['foo'] = 'foo';
$array['bar'] = 'bar';
$array['baz'] = 'baz';  

$foo = 'local foo';
$bar = 'local bar';

extract($array, EXTR_PREFIX_SAME, 'pre');

print_r(get_defined_vars());

//partial output    
//Array
//(
//  [array] => Array
//      (
//          [foo] => foo
//          [bar] => bar
//          [baz] => baz
//      )
//
//  [foo] => local foo
//  [bar] => local bar
//  [pre_foo] => foo
//  [pre_bar] => bar
//  [baz] => baz
//) 

So with EXTR_PREFIX_SAME, the values of $foo and $bar will remain the same, and three new local variables ($pre_foo, $pre_bar, and $baz) will be defined. However if we use EXTR_PREFIX_IF_EXISTS

$array = Array();
$array['foo'] = 'foo';
$array['bar'] = 'bar';
$array['baz'] = 'baz';  

$foo = 'local foo';
$bar = 'local bar';

extract($array, EXTR_PREFIX_IF_EXISTS, 'pre');

print_r(get_defined_vars());

//partial output    
//Array
//(
//  [array] => Array
//      (
//          [foo] => foo
//          [bar] => bar
//          [baz] => baz
//      )
//
//  [foo] => local foo
//  [bar] => local bar
//  [pre_foo] => foo
//  [pre_bar] => bar
//)     

The values of $foo and $bar are still preserved, but only TWO new variables are imported into the local space. Since $baz isn't a variable that already exists the EXTR_PREFIX_IF_EXISTS tells PHP to ignore the 'baz' key in the array.

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