Question

This question already has an answer here:

I'm doing some web scraping and sites frequently use HTML entities to represent non ascii characters. Does Python have a utility that takes a string with HTML entities and returns a unicode type?

For example:

I get back:

ǎ

which represents an "ǎ" with a tone mark. In binary, this is represented as the 16 bit 01ce. I want to convert the html entity into the value u'\u01ce'

Was it helpful?

Solution

The standard lib’s very own HTMLParser has an undocumented function unescape() which does exactly what you think it does:

import HTMLParser
h = HTMLParser.HTMLParser()
h.unescape('© 2010') # u'\xa9 2010'
h.unescape('© 2010') # u'\xa9 2010'

OTHER TIPS

Python has the htmlentitydefs module, but this doesn't include a function to unescape HTML entities.

Python developer Fredrik Lundh (author of elementtree, among other things) has such a function on his website, which works with decimal, hex and named entities:

import re, htmlentitydefs

##
# Removes HTML or XML character references and entities from a text string.
#
# @param text The HTML (or XML) source text.
# @return The plain text, as a Unicode string, if necessary.

def unescape(text):
    def fixup(m):
        text = m.group(0)
        if text[:2] == "&#":
            # character reference
            try:
                if text[:3] == "&#x":
                    return unichr(int(text[3:-1], 16))
                else:
                    return unichr(int(text[2:-1]))
            except ValueError:
                pass
        else:
            # named entity
            try:
                text = unichr(htmlentitydefs.name2codepoint[text[1:-1]])
            except KeyError:
                pass
        return text # leave as is
    return re.sub("&#?\w+;", fixup, text)

Use the builtin unichr -- BeautifulSoup isn't necessary:

>>> entity = '&#x01ce'
>>> unichr(int(entity[3:],16))
u'\u01ce'

An alternative, if you have lxml:

>>> import lxml.html
>>> lxml.html.fromstring('&#x01ce').text
u'\u01ce'

If you are on Python 3.4 or newer, you can simply use the html.unescape:

import html

s = html.unescape(s)

You could find an answer here -- Getting international characters from a web page?

EDIT: It seems like BeautifulSoup doesn't convert entities written in hexadecimal form. It can be fixed:

import copy, re
from BeautifulSoup import BeautifulSoup

hexentityMassage = copy.copy(BeautifulSoup.MARKUP_MASSAGE)
# replace hexadecimal character reference by decimal one
hexentityMassage += [(re.compile('&#x([^;]+);'), 
                     lambda m: '&#%d;' % int(m.group(1), 16))]

def convert(html):
    return BeautifulSoup(html,
        convertEntities=BeautifulSoup.HTML_ENTITIES,
        markupMassage=hexentityMassage).contents[0].string

html = '<html>&#x01ce;&#462;</html>'
print repr(convert(html))
# u'\u01ce\u01ce'

EDIT:

unescape() function mentioned by @dF which uses htmlentitydefs standard module and unichr() might be more appropriate in this case.

This is a function which should help you to get it right and convert entities back to utf-8 characters.

def unescape(text):
   """Removes HTML or XML character references 
      and entities from a text string.
   @param text The HTML (or XML) source text.
   @return The plain text, as a Unicode string, if necessary.
   from Fredrik Lundh
   2008-01-03: input only unicode characters string.
   http://effbot.org/zone/re-sub.htm#unescape-html
   """
   def fixup(m):
      text = m.group(0)
      if text[:2] == "&#":
         # character reference
         try:
            if text[:3] == "&#x":
               return unichr(int(text[3:-1], 16))
            else:
               return unichr(int(text[2:-1]))
         except ValueError:
            print "Value Error"
            pass
      else:
         # named entity
         # reescape the reserved characters.
         try:
            if text[1:-1] == "amp":
               text = "&amp;amp;"
            elif text[1:-1] == "gt":
               text = "&amp;gt;"
            elif text[1:-1] == "lt":
               text = "&amp;lt;"
            else:
               print text[1:-1]
               text = unichr(htmlentitydefs.name2codepoint[text[1:-1]])
         except KeyError:
            print "keyerror"
            pass
      return text # leave as is
   return re.sub("&#?\w+;", fixup, text)

Not sure why the Stack Overflow thread does not include the ';' in the search/replace (i.e. lambda m: '&#%d*;*') If you don't, BeautifulSoup can barf because the adjacent character can be interpreted as part of the HTML code (i.e. &#39B for &#39Blackout).

This worked better for me:

import re
from BeautifulSoup import BeautifulSoup

html_string='<a href="/cgi-bin/article.cgi?f=/c/a/2010/12/13/BA3V1GQ1CI.DTL"title="">&#x27;Blackout in a can; on some shelves despite ban</a>'

hexentityMassage = [(re.compile('&#x([^;]+);'), 
lambda m: '&#%d;' % int(m.group(1), 16))]

soup = BeautifulSoup(html_string, 
convertEntities=BeautifulSoup.HTML_ENTITIES, 
markupMassage=hexentityMassage)
  1. The int(m.group(1), 16) converts the number (specified in base-16) format back to an integer.
  2. m.group(0) returns the entire match, m.group(1) returns the regexp capturing group
  3. Basically using markupMessage is the same as:
    html_string = re.sub('&#x([^;]+);', lambda m: '&#%d;' % int(m.group(1), 16), html_string)

Another solution is the builtin library xml.sax.saxutils (both for html and xml). However, it will convert only &gt, &amp and &lt.

from xml.sax.saxutils import unescape

escaped_text = unescape(text_to_escape)

Here is the Python 3 version of dF's answer:

import re
import html.entities

def unescape(text):
    """
    Removes HTML or XML character references and entities from a text string.

    :param text:    The HTML (or XML) source text.
    :return:        The plain text, as a Unicode string, if necessary.
    """
    def fixup(m):
        text = m.group(0)
        if text[:2] == "&#":
            # character reference
            try:
                if text[:3] == "&#x":
                    return chr(int(text[3:-1], 16))
                else:
                    return chr(int(text[2:-1]))
            except ValueError:
                pass
        else:
            # named entity
            try:
                text = chr(html.entities.name2codepoint[text[1:-1]])
            except KeyError:
                pass
        return text # leave as is
    return re.sub("&#?\w+;", fixup, text)

The main changes concern htmlentitydefs that is now html.entities and unichr that is now chr. See this Python 3 porting guide.

Licensed under: CC-BY-SA with attribution
Not affiliated with StackOverflow
scroll top