How to join two table without getting duplicate from right table in Oracle

Question

Tables Details:

CREATE TABLE Test2 (
  ID INT,
  Value INT,
  other INT);
  
CREATE TABLE Test1 (
  ID INT,
  TYPE INT,
  other INT);
  
INSERT INTO Test2 VALUES (123456, 5, 12);


INSERT INTO Test1 VALUES (123456, 00, 2);
INSERT INTO Test1 VALUES (123456, 01, 6);
INSERT INTO Test1 VALUES (123456, 02, 4);

INSERT INTO Test1 VALUES (987654, 00, 7);
INSERT INTO Test1 VALUES (987654, 01, 8);

INSERT INTO Test1 VALUES (456789, 00, 6);
INSERT INTO Test1 VALUES (456789, 01, 16);

This is the Query i m using to avoid duplicate from table Test

SELECT DISTINCT t1.ID, t1.TYPE, t1.other, t2.value  
FROM Test1 t1 INNER JOIN Test2 t2 ON t1.ID = t2.ID
GROUP BY t1.ID, t1.TYPE, t1.other, t2.value
ORDER BY t1.ID ASC;

Query Result:

ID  TYPE    other   value
123456  0   2   5
123456  1   6   5
123456  2   4   5

Description:

Expected Result is , when i m fetching match records from tables. Should get all the records from left table(Test1) and avoid duplicate record from right table (Test2).

Expected Query Result are,

ID  TYPE    other   value
123456  0   2   5
123456  1   6   
123456  2   4

SQL Fiddle Link

http://sqlfiddle.com/#!9/8953fc/29

Criteria When there is ID match should get all matched records from left table (Test1) and from right table (Test2) should get distinct records.

Answer 1

Doing it on client side (sqlplus):

SQL> SELECT DISTINCT t1.ID, t1.TYPE, t1.other, t2.value FROM Test1 t1 INNER JOIN Test2 t2 ON t1.ID = t2.ID GROUP BY t1.ID, t1.TYPE, t1.other, t2.value ORDER BY t1.ID ASC;

        ID       TYPE      OTHER      VALUE
---------- ---------- ---------- ----------
    123456          0          2          5
    123456          1          6          5
    123456          2          4          5

SQL> break on value
SQL> SELECT DISTINCT t1.ID, t1.TYPE, t1.other, t2.value FROM Test1 t1 INNER JOIN Test2 t2 ON t1.ID = t2.ID GROUP BY t1.ID, t1.TYPE, t1.other, t2.value ORDER BY t1.ID ASC;

        ID       TYPE      OTHER      VALUE
---------- ---------- ---------- ----------
    123456          0          2          5
    123456          1          6
    123456          2          4

In SQL:

SQL> clear breaks
breaks cleared
SQL> SELECT DISTINCT t1.ID, t1.TYPE, t1.other, t2.value FROM Test1 t1 INNER JOIN Test2 t2 ON t1.ID = t2.ID GROUP BY t1.ID, t1.TYPE, t1.other, t2.value ORDER BY t1.ID ASC;

        ID       TYPE      OTHER      VALUE
---------- ---------- ---------- ----------
    123456          0          2          5
    123456          1          6          5
    123456          2          4          5

SQL> SELECT DISTINCT t1.ID, t1.TYPE, t1.other, case when row_number() over (partition by t1.id order by t1.id) = 1 then t2.value end value FROM Test1 t1 INNER JOIN Test2 t2 ON t1.ID = t2.ID GROUP BY t1.ID, t1.TYPE, t1.other, t2.value ORDER BY t1.ID ASC;

        ID       TYPE      OTHER      VALUE
---------- ---------- ---------- ----------
    123456          0          2          5
    123456          1          6
    123456          2          4