How can I get all field values from a query with JOINed tables?

Question

I have this elementary query:

SELECT d.description, o.code FROM order_positions AS o
LEFT JOIN article_descriptions AS d ON (o.article_id = d.article_id)
WHERE o.order_id = 1

and I'm using MDB2 from PEAR to execute it and read the return values.

But somehow the result array always contains fields from the order_positions table only!, i.e. the result array looks like this

row[code] = 'abc123'

while I want it to look like this

row[description] = 'my description'
row[code] = 'abc123'

I already tried the following:

• Vary the order of the fields, i.e. code first, then description.
• Vary the order of the joined tables.
• Used full table names instead of aliases.
• Used the "MySQL join" instead (SELECT FROM table1, table2 WHERE table1.id = table2.id)
• Used aliases with and without AS.

Some other facts:

• Executing this query in MySQL Query Browser works fine, all fields are returned.
• The order_positions table seems to be preferred, no matter what. When joining with additional tables I still only get fields from this table.

Answer 1

OK, I found the cause:

Fields with NULL values are not added to the array. In my test scenario description was in fact null and hence was not available in the array.

I'll still keep this (embarrassing) question, just in case someone else has this problem in the future.

Facepalm http://www.scienceblogs.de/frischer-wind/picard-facepalm-thumb-512x409.jpg

Answer 2

This should work:

SELECT d.description, o.code 
FROM order_positions o, article_descriptions d 
WHERE o.order_id = 1 AND d.article_id = o.article_id

Answer 3

Are you sure you're not using fetchOne() by mistake instead of fetchRow()?

Could you post your PHP code?

Another possibility is that in your code you missed the comma:

SELECT a b

is the same as

SELECT a AS b