Select records from NOW() -1 Day

Question

Is there a way in a MySQL statement to order records (through a date stamp) by >= NOW() -1 so all records from the day before today to the future are selected?

Answer 1

Judging by the documentation for date/time functions, you should be able to do something like:

SELECT * FROM FOO
WHERE MY_DATE_FIELD >= NOW() - INTERVAL 1 DAY

Answer 2

Be aware that the result may be slightly different than you expect.

NOW() returns a DATETIME.

And INTERVAL works as named, e.g. INTERVAL 1 DAY = 24 hours.

So if your script is cron'd to run at 03:00, it will miss the first three hours of records from the 'oldest' day.

To get the whole day use CURDATE() - INTERVAL 1 DAY. This will get back to the beginning of the previous day regardless of when the script is run.

Answer 3

You're almost there: it's NOW() - INTERVAL 1 DAY

Answer 4

Didn't see any answers correctly using DATE_ADD or DATE_SUB:

Subtract 1 day from NOW()

...WHERE DATE_FIELD >= DATE_SUB(NOW(), INTERVAL 1 DAY)

Add 1 day from NOW()

...WHERE DATE_FIELD >= DATE_ADD(NOW(), INTERVAL 1 DAY)

Answer 5

Sure you can:

SELECT * FROM table
WHERE DateStamp > DATE_ADD(NOW(), INTERVAL -1 DAY)

Answer 6

when search field is timestamp and you want find records from 0 hours yesterday and 0 hour today use construction

MY_DATE_TIME_FIELD between makedate(year(now()), date_format(now(),'%j')-1) and makedate(year(now()), date_format(now(),'%j'))  

instead

 now() - interval 1 day