Optional number of wildcards in URL patterns in Django

Question

#views.py
def sum(*args):
    return reduce((lambda x, y: int(x)+int(y)), args)

Is it possible to write one URL pattern that will handle uniformly such requests as /sum/1/2 (result = 3), /sum/1/2/3 (result = 6), etc.?

Answer 1

It's not exactly what you want, but you could use

(r'^sum/(?P<allargs>[/0-9]+)$', 'views.sum')

and then

def sum(request, allargs):
    args = map( int, allargs.split('/') )
    # Compute sum

Answer 2

Unless you absolutely want to use the form "/1/2/3", you'd rather use query string "/sum?1&2&3". It will be much simpler to implement.