Question

I'm new to XSLT and I can't resolve the following problem:

I have a xml file like this:

<root>
    <subset>
        <e id="A"></e>
        <e id="C"></e>
    </subset>

    <data>
        <info id="A" order="3" name="ANode"></info>
        <info id="B" order="4" name="BNode"></info>
        <info id="C" order="1" name="CNode"></info>
        <info id="D" order="2" name="DNode"></info>
    </data>
</root>

And I want to produce this:

<root>
    <newnode id="C" order="1" name="CNode"></newnode>
    <newnode id="A" order="3" name="ANode"></newnode>
</root>

As you can see the idea is to "complete" the subset of ids by retrieving the respective info, and sort them accordingly to their order specified on <data>.

Notice that <data> is supposed to have a lot of child nodes.

Also, I'm separating the nodes with the information on the <data> element from the subsets of ids, because I will have many subsets and I don't want to have repeated information "everywhere".

Thanks in advance.

Was it helpful?

Solution

You could also key off of the subset depending upon what else you may need to do with your actual data.

<xsl:output indent="yes" />

<xsl:key name="subset" match="e" use="@id" />

<xsl:template match="/">
    <root>
    <xsl:for-each select="//info[count(key('subset',@id)[1]) &gt; 0]">
        <xsl:sort select="@order" data-type="number" />
        <newnode id="{@id}" order="{@order}" name="{@name}" />
    </xsl:for-each>
    </root>
</xsl:template>

OTHER TIPS

Cross-references ask for using keys:

<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="1.0">

  <xsl:output indent="yes"/>

  <xsl:key name="k1" match="info" use="@id"/>

  <xsl:template match="root">
    <xsl:copy>
      <xsl:apply-templates select="subset/e">
        <xsl:sort select="key('k1', @id)/@order" data-type="number"/>
      </xsl:apply-templates>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="e">
    <newnode id="{@id}" order="{key('k1', @id)/@order}" name="{key('k1', @id)/@name}"/>
  </xsl:template>

</xsl:stylesheet>

That should do for the input sample you presented.

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