Can you register an existing instance of a type in the Windsor Container?
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01-07-2019 - |
Question
In the Windsor IOC container is it possible to register a type that I've already got an instance for, instead of having the container create it?
Solution
There is a AddComponentInstance method on the Container's Kernel property.
From the Unit Tests:
[Test]
public void AddComponentInstance()
{
CustomerImpl customer = new CustomerImpl();
kernel.AddComponentInstance("key", typeof(ICustomer), customer);
Assert.IsTrue(kernel.HasComponent("key"));
CustomerImpl customer2 = kernel["key"] as CustomerImpl;
Assert.AreSame(customer, customer2);
customer2 = kernel[typeof(ICustomer)] as CustomerImpl;
Assert.AreSame(customer, customer2);
}
[Test]
public void AddComponentInstance_ByService()
{
CustomerImpl customer = new CustomerImpl();
kernel.AddComponentInstance <ICustomer>(customer);
Assert.AreSame(kernel[typeof(ICustomer)],customer);
}
[Test]
public void AddComponentInstance2()
{
CustomerImpl customer = new CustomerImpl();
kernel.AddComponentInstance("key", customer);
Assert.IsTrue(kernel.HasComponent("key"));
CustomerImpl customer2 = kernel["key"] as CustomerImpl;
Assert.AreSame(customer, customer2);
customer2 = kernel[typeof(CustomerImpl)] as CustomerImpl;
Assert.AreSame(customer, customer2);
}
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