Portable way to get file size in C/C++

Question

I need to determin the byte size of a file.

The coding language is C++ and the code should work with Linux, windows and any other operating system. This implies using standard C or C++ functions/classes.

This trivial need has apparently no trivial solution.

Answer 1

Using std's stream you can use:

std::ifstream ifile(....);
ifile.seekg(0, std::ios_base::end);//seek to end
//now get current position as length of file
ifile.tellg();

If you deal with write only file (std::ofstream), then methods are some another:

ofile.seekp(0, std::ios_base::end);
ofile.tellp();

Answer 2

You can use stat system call:

#ifdef WIN32 
_stat64()
#else
stat64()

Answer 3

If you only need the file size this is certainly overkill but in general I would go with Boost.Filesystem for platform-independent file operations. Amongst other attribute functions it contains

template <class Path> uintmax_t file_size(const Path& p);

You can find the reference here. Although Boost Libraries may seem huge I found it to often implement things very efficiently. You could also only extract the function you need but this might proof difficult as Boost is rather complex.

Answer 4

Simples:

std::ifstream ifs; 
ifs.open("mybigfile.txt", std::ios::bin); 
ifs.seekg(0, std::ios::end); 
std::fpos pos = ifs.tellg();

Answer 5

Often we want to get things done in the most portable manner, but in certain situations, especially like this, I would strongly recommend using system API's for best performance.

Answer 6

Portability requires you to use the least common denominators, which would be C. (not c++) The method that I use is the following.

#include <stdio.h>

long filesize(const char *filename)
{
FILE *f = fopen(filename,"rb");  /* open the file in read only */

long size = 0;
  if (fseek(f,0,SEEK_END)==0) /* seek was successful */
      size = ftell(f);
  fclose(f);
  return size;
}