GPath to find if a table header contains a matching string

StackOverflow https://stackoverflow.com/questions/9260461

  •  29-04-2021
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Question

I'm parsing an HTML file into a well-formed XML document using NekoHTML parser. However I can't quite figure out the GPath so that I can identify the table that has the "Settings" string.

def parser = new org.cyberneko.html.parsers.SAXParser()
parser.setFeature('http://xml.org/sax/features/namespaces', false)

    def html = 
    ''' 
        <html>
            <title>Hiya!</title>
        </html>
        <body>
            <table>
                <tr>
                    <th colspan='3'>Settings</th>
                    <td>First cell r1</td>
                    <td>Second cell r1</td>
                </tr>
            </table>
            <table>
                <tr>
                    <th colspan='3'>Other Settings</th>
                    <td>First cell r2</td>
                    <td>Second cell r2</td>
                </tr>
            </table>
    '''

    def slurper = new XmlSlurper(parser)
    def page = slurper.parseText(html)

In this sample, the first table should be selected so that I can iterate over other row values in it. Can someone help me with this GPath please?

EDIT: Side question - why does

println page.HTML.HEAD.TITLE

print an empty string, shouldn't it return the title?

Was it helpful?

Solution

  1. To get the table with 'Settings' in the header, you should be able to do:

    def settingsTableNode = page.BODY.TABLE.find { table ->
  table.TBODY.TR.TH.text() == 'Settings'
}

  2. page points to the root of the document, so you don't need the HTML. All you should need to do is:

    println page.HEAD.TITLE
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