Question

i am using XML as my backend for the application...

LXML is used to parse the xml.

How can i encrypt this xml file to make sure that the data is protected......

thanks in advance.

Was it helpful?

Solution

As XML contains repetitive structure it is better to first compress and then encrypt it.

Download and install PyDes.

from pyDes import *
import bz2

def encrypt(data,password):
    k = des(password, CBC, "\0\0\0\0\0\0\0\0", pad=None, padmode=PAD_PKCS5)
    d = k.encrypt(data)
    return d

def decrypt(data,password):
    k = des(password, CBC, "\0\0\0\0\0\0\0\0", pad=None, padmode=PAD_PKCS5)
    d = k.decrypt(data)
    return d

password = "eight222" # password length should be 8

data = '''
<?xml version="1.0"?>
  <library>
   <shelf id="fiction">
    <book>
     <title>Of Mice and Men</title>
     <author>John Steinbeck</author>
    </book>
    <book>
     <title>Harry Potter and the Philosopher's Stone</title>
     <author>J.K. Rowling</author>
    </book>
   </shelf>
  </library> 
'''

print len(data)

compressed_data = bz2.compress(data)
print len(compressed_data)

encrypted_data = encrypt(compressed_data,password)

print "%r"%encrypted_data

uncompressed_encrypted_data = encrypt(data,password)

print len(encrypted_data)
print len(uncompressed_encrypted_data)
print bz2.decompress(decrypt(encrypted_data,password))

There are lots of cryptography libraries available in python

  1. Pure-Python RSA implementation
  2. Python Encryption Examples
  3. PyXMLSec
  4. PyCrypto - The Python Cryptography Toolkit
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