Generic methods and optional arguments

Question

Is it possible to write similar construction?
I want to set, somehow, default value for argument of type T.

    private T GetNumericVal<T>(string sColName, T defVal = 0)
    {
        string sVal = GetStrVal(sColName);
        T nRes;
        if (!T.TryParse(sVal, out nRes))
            return defVal;

        return nRes;
    }

Additionally, I found following link: Generic type conversion FROM string
I think, this code must work

private T GetNumericVal<T>(string sColName, T defVal = default(T)) where T : IConvertible
{
    string sVal = GetStrVal(sColName);
    try
    {
        return (T)Convert.ChangeType(sVal, typeof(T));
    }
    catch (FormatException)
    {
        return defVal;
    }            
}

Answer 1

I haven't tried this but change T defVal = 0 to T defVal = default(T)

Answer 2

If you know that T will have a parameterless constructor you can use new T() as such:

private T GetNumericVal<T>(string sColName, T defVal = new T()) where T : new()

Otherwise you can use default(T)

private T GetNumericVal<T>(string sColName, T defVal = default(T))

Answer 3

To answer the question that would work to set the default value

private T GetNumericVal<T>(string sColName, T defVal = default(T)) 
{
    string sVal = GetStrVal(sColName);
    T nRes;
    if (!T.TryParse(sVal, out nRes))
        return defVal;

    return nRes;
}

But you cannot call the static TryParse method since the compiler has no way to know type T declares this static method.