Is that possible to divide all elements in C# double list to that double list elements sum (which makes total = 1)

Question

Imagine a doube list like the follow

List<double> lstDouble=new List<double>{4,6,2,7,1,1};

So what i want is dividing all elements in this list to sum of the elements(21).

So the list becomes after dividing :

lstDouble = {4/21,6/21,2/21,7/21,1/21,1/21}

Which would mean that the new sum of the elements = 1

I can do that via iteration etc but i wonder are there any short way since Matlab has. And my assistant professor keep telling me that learn Matlab and use it but i don't want :D I love C#

Thank you.

C# 4.0 WPF application

Answer 1

var sum = lstDouble.Sum();
var result = lstDouble.Select(d => d / sum);

• Enumerable.Sum Method
• Enumerable.Select Method

Answer 2

You can do this with LINQ:

var sum = lstDouble.Sum();
var newLst = lstDouble.Select( x => x/sum );

Answer 3

Use a lambda expression:

 lstDouble.ForEach(x => x = x/21);

Answer 4

var sum = lstDouble.Sum();
var result = lstDouble.Select(v => v / sum);

Answer 5

This is a pseudo code:

double sum = 0;
for(int i=0; i<array.length; i++)
   sum+=array[i];
for(int i=0; i<array.length; i++)
   array[i]=array[i]/sum;