How to declare an unsigned 32-bit integer?

Question

Is there a way to declare a 32-bit unsigned integer in PowerShell?

I'm trying to add an unsigned (begin with 0xf) i.e. 0xff000000 + 0xAA, but it turned out to be a negative number whereas I want it to be 0xff0000AA.

Answer 1

0xff00000AA is too large for a 32 bit unsigned integer, use uint64

PS> [uint64]0xff00000AA
68451041450

Answer 2

The code from the currently accepted answer causes the following error on my system:

This is because PowerShell always tries to convert hex values to int first so even if you cast to uint64, the environment will complain if the number has a negative int value. You can see this from the following example:

PS C:\> [uint64] (-1)
Cannot convert value "-1" to type "System.UInt64". Error: "Value was either too large or too small for a UInt64."
At line:1 char:26
+ Invoke-Expression $ENUS; [uint64] (-1)
+                          ~~~~~~~~~~~~~
    + CategoryInfo          : InvalidArgument: (:) [], RuntimeException
    + FullyQualifiedErrorId : InvalidCastIConvertible

You need to cast the string representation of the number to uint64 to avoid this:

[uint64]"0xff000000" + [uint64]"0xAA"

Answer 3

I'm assuming you meant 0xff0000AA since, as others have mentioned, 0xff00000AA is an overflow.

The easiest way to do this is to convert the value from a string. You can either use System.Convert:

[System.Convert]::ToUInt32('0xff0000AA',16)
[System.Convert]::ToUInt32('ff0000AA',16)

Or just try to cast the string, but in this case you need to prepend the 0x:

[uint32]'0xff0000AA'

If, on the other hand, you really did want to know the 32-bit unsigned integer portion of the 64-bit number `0xff00000aa', then you could do this:

[System.Convert]::ToUInt32([System.Convert]::ToString(0xff00000AA -band ([uint32]::MaxValue),16),16)

Answer 4

The simplest way is to cast to [uint32] from a long literal (with the L suffix). You don't need to do the math in [uint64] or cast from a string

[uint32]0xff000000L + 0xAA

In PowerShell 6.2 a series of new suffixes have been added including a u suffix fof uint32 so this can be done even simpler

0xff000000u + 0xAA