How to get random double value out of random byte array values?
Question
I would like to use RNGCryptoServiceProvider as my source of random numbers. As it only can output them as an array of byte values how can I convert them to 0 to 1 double value while preserving uniformity of results?
Solution
byte[] result = new byte[8];
rng.GetBytes(result);
return (double)BitConverter.ToUInt64(result,0) / ulong.MaxValue;
OTHER TIPS
This is how I would do this.
private static readonly System.Security.Cryptography.RNGCryptoServiceProvider _secureRng;
public static double NextSecureDouble()
{
var bytes = new byte[8];
_secureRng.GetBytes(bytes);
var v = BitConverter.ToUInt64(bytes, 0);
// We only use the 53-bits of integer precision available in a IEEE 754 64-bit double.
// The result is a fraction,
// r = (0, 9007199254740991) / 9007199254740992 where 0 <= r && r < 1.
v &= ((1UL << 53) - 1);
var r = (double)v / (double)(1UL << 53);
return r;
}
Coincidentally
9007199254740991 / 9007199254740992 is ~= 0.99999999999999988897769753748436
which is what theRandom.NextDouble
method will return as it's maximum value (see https://msdn.microsoft.com/en-us/library/system.random.nextdouble(v=vs.110).aspx).
In general, the standard deviation of a continuous uniform distribution is (max - min) / sqrt(12).
With a sample size of 1000 I'm reliably getting within a 2% error margin.
With a sample size of 10000 I'm reliably getting within a 1% error margin.
Here's how I verified these results.
[Test]
public void Randomness_SecureDoubleTest()
{
RunTrials(1000, 0.02);
RunTrials(10000, 0.01);
}
private static void RunTrials(int sampleSize, double errorMargin)
{
var q = new Queue<double>();
while (q.Count < sampleSize)
{
q.Enqueue(Randomness.NextSecureDouble());
}
for (int k = 0; k < 1000; k++)
{
// rotate
q.Dequeue();
q.Enqueue(Randomness.NextSecureDouble());
var avg = q.Average();
// Dividing by n−1 gives a better estimate of the population standard
// deviation for the larger parent population than dividing by n,
// which gives a result which is correct for the sample only.
var actual = Math.Sqrt(q.Sum(x => (x - avg) * (x - avg)) / (q.Count - 1));
// see http://stats.stackexchange.com/a/1014/4576
var expected = (q.Max() - q.Min()) / Math.Sqrt(12);
Assert.AreEqual(expected, actual, errorMargin);
}
}
You can use the BitConverter.ToDouble(...) method. It takes in a byte array and will return a Double. Thre are corresponding methods for most of the other primitive types, as well as a method to go from the primitives to a byte array.
Use BitConverter to convert a sequence of random bytes to a Double:
byte[] random_bytes = new byte[8]; // BitConverter will expect an 8-byte array
new RNGCryptoServiceProvider().GetBytes(random_bytes);
double my_random_double = BitConverter.ToDouble(random_bytes, 0);